Consider the following data drawn independently from normally distributed populations: (You may find it useful to reference the appropriate table: z table or ttable) X1 = -28.3 $1 = 8.7 n₁ = 22 X2 = -18.5 $₂² = 7.9 n2 = 16 a. Construct the 95% confidence interval for the difference between the population means. Assume the population variances are unknown but equal. (Round final answers to 2 decimal places.) Confidence interval is to

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**Consider the following data drawn independently from normally distributed populations**: *(You may find it useful to reference the appropriate table: [z table](#) or [t table](#))*

\[
\overline{X}_1 = -28.3 \quad \quad \quad \overline{X}_2 = -18.5
\]
\[
s_1^2 = 8.7 \quad \quad \quad s_2^2 = 7.9
\]
\[
n_1 = 22 \quad \quad \quad n_2 = 16
\]

**a.** Construct the 95% confidence interval for the difference between the population means. Assume the population variances are unknown but equal. *(Round final answers to 2 decimal places.)*

Confidence interval is [  \_\_\_ ] to [  \_\_\_  ].
Transcribed Image Text:**Consider the following data drawn independently from normally distributed populations**: *(You may find it useful to reference the appropriate table: [z table](#) or [t table](#))* \[ \overline{X}_1 = -28.3 \quad \quad \quad \overline{X}_2 = -18.5 \] \[ s_1^2 = 8.7 \quad \quad \quad s_2^2 = 7.9 \] \[ n_1 = 22 \quad \quad \quad n_2 = 16 \] **a.** Construct the 95% confidence interval for the difference between the population means. Assume the population variances are unknown but equal. *(Round final answers to 2 decimal places.)* Confidence interval is [ \_\_\_ ] to [ \_\_\_ ].
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