Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the population has a normal distribution. The principal randomly selected six students to take an aptitude test. Their scores were: 88.0 84.1 74.9 83.283.7 85.5 Determine a 90% confidence interval for the mean score for all students.

Q: Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 30.…

A:

Q: e: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the…

A: Sample size n =47 Sample mean=109 Population standard deviation =32

Q: Find the indicated margin of error. Out of 260 trials, 150 turned out positive. Find the margin of…

A: It is given that the sample size (n) is 260 and the number of positive trials (x) is 150.

Q: Find the indicated margin of error. Out of 330 trials, 150 turned out positive. Find the margin of…

A:

Q: fashion designer wants to know how many new dresses women buy each year.  A sample of 502 women was…

A:

Q: Using the sample paired data below, construct a 95% confidence interval for the population mean of…

A: The difference is, x y Difference(x-y) 5.1 4.7 0.4 5.0 3.9 1.1 4.6 4.1 0.5 3.5 4.2 -0.7…

Q: Construct the indicated confidence interval for the difference between population proportions p1 -…

A:

Q: Construct the confidence interval for the population mean y. C=0.95, x= 16.7, o= 4.0, and n= 75. A…

A: Here, C=0.95, x=16.7, σ=4.0, and n=75.

Q: Use the data about the sample to calculate a 95% confidence interval for the average income of…

A: 1. The conditions for using t-distribution are: Sample size is small. Population standard deviation…

Q: Find a 95% confidence interval for a mean, µ, where n = 324, x̄ = 2.7, s = .91, and se = .06.

A: Given: n = 324, x̄ = 2.7, s = .91, se = .06.

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: Solution-: Given: x¯=83.97,n=76,σ=13.89  Use this information to construct the​ 90% and​ 95%…

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: Given Data: Confidence level - 90%: The expression for the confidence level is,

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A:

Q: Find the margin of error for the 95% confidence interval used to estimate the population proportion.…

A: Confidence level = 95% Sample size (n) = 2440 Sample proportion (p̂) = 0.70

Q: For a sampling distribution of n = 500 and population proportion of 0.48 of those who prefer cookies…

A:

Q: In a random sample of seven ​people, the mean driving distance to work was 20.2 miles and the…

A:

Q: In a random sample of five ​people, the mean driving distance to work was 19.9 miles and the…

A: Given Sample size, n = 5 Degree of freedom, n-1 = 4 Sample mean, x = 19.9 miles Sample standard…

Q: Construct the indicated confidence interval for the population mean . Assume c = 0.98, = 101.3, =…

A:

Q: A statistics practitioner took a random sample of 56 observations from a population whose standard…

A: We have given that,  Sample size (n) = 56, population standard deviation (σ) = 35 and sample mean…

Q: Use the given data to find the 95% confidence interval estimate of the population mean u. Assume…

A: Given data: sample size = 25 Standard deviation = 13 Sample mean = 106 Confidence level = 95%

Q: Construct the confidence interval for the population mean y. C= 0.90, x=16.6, o= 10.0, and n= 80

A: Here, C=0.90, x=16.6, σ=10.0, and n=80.

Q: Find ??/2 for the 93% confidence interval. Select one: A. 1.83 B. 1.81 C. 1.80 D. 1.82

A: Solution: Given information: Confidence level = 93% = 0.93 α=1-confidence level α=1-0.93= 0.07…

Q: You are given the sample mean and the population standard deviation. Use this information to…

A:

Q: The principal randomly selected six students to take an aptitude test. Their scores were:…

A: The sample mean and standard deviation are, The degree of freedom is, df=n-1   =6-1   =5

Q: Construct the indicated confidence interval for the difference between population proportions p1-p2.…

A:

Q: The number of successes and the sample size are given for a simple random sample from a population.…

A: Obtain the value of sample proportion. The value of sample proportion is obtained below: From the…

Q: The baseball coach tracked how long it took 8 of his players to do a series of drills.  The times…

A: We have given the times recorded (in minutes) of 8 players.

Q: Javier wants to estimate the percentage of people who have purchased a used car. He surveys 250…

A: From the provided information, Sample size (n) = 250 From which 212 have purchased a used car.…

Q: A statistics practitioner took a random sample of 43 Note: For each confidence interval, enter your…

A: n = 43 standard deviation = 27 mean = 104 95% confidence interval for mean is given by  x±zα2*σn 104…

Q: atistics practitioner took a random sample of 49 observations from a population whose standard…

A: Sample size n =49 Sample mean=103 Population standard deviation =25

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: random sample of 45 business​ days, the mean closing price of a certain stock was​$111.24.Assume the…

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Given, Sample size = 30 Sample mean = 95 Sample standard deviation = 6.6   Since the population…

Q: In a random sample of twelve ​people, the mean driving distance to work was 22.4 miles and the…

A: Given: n=12 , x̄=22.4 miles, S= 7.3 miles (1-α)%= 99%  1-α= 0.99 α= 0.01 α/2=0.005  df = n -1 = 12 -…

Q: Suppose you calculate a 95% confidence interval for a proportion to to be: 0.39 to 0.78. Determine…

A: Given,   Lower bound = 0.39​ Upper bound = 0.78   Here, we use to determine the margin of error.