Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.t Suppose a small group of 15 Allen's hummingbirds has been under study in Arizona. The average vor these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with o = 0.30 gram.(a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.)lower limitupper limitmargin of error(b) What conditions are necessary for your calculations? (Select all that apply.)uniform distribution of weightsn is largenormal distribution of weightso is unknownVo is known(c) Interpret your results in the context of this problem.OWe are 80% confident that the true average weight of Allen's hummingbirds falls within thisinterval.The probability that this interval contains the true average weight of Allen's hummingbirds is0.80.O We are 20% confident that the true average weight of Allen's hummingbirds falls within thisinterval.The probability that this interval contains the true average weight of Allen's hummingbirds is0.20.Aol.i 725Σ

Sample mean = x̅ = 3.15 Sample size = n = 15 Population S.D = σ = 0.3 Standard Error = σ/√n =…

llen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.t Suppose a small group of 15 Allen's hummingbirds has been under study in Arizona. The average or these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with o = 0.30 gram. (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error

llen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.t Suppose a small group of 15 Allen's hummingbirds has been under study in Arizona. The average or these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with o = 0.30 gram. (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

do fast ..with explanation both require..
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.† Suppose a small group of 11 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with ? = 0.32 gram. (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit __ upper limit __ margin of error __ (b) What conditions are necessary for your calculations? (Select all that apply.) A-n is large B-? is unknown C-? is know D-nnormal distribution of weights E-uniform distribution of weights (c) MUTIPLE CHOICE Interpret your results in the context of this problem. A-We are 20% confident that the true average weight of Allen's hummingbirds falls within this interval. B-The probability that this…
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.† Suppose a small group of 10 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with ? = 0.28 gram. (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error b) Interpret your results in the context of this problem: choose one. -We are 80% confident that the true average weight of Allen's hummingbirds falls within this interval. -The probability that this interval contains the true average weight of Allen's hummingbirds is 0.20. -We are 20% confident that the true average weight of Allen's hummingbirds falls within this interval. -The probability that…
Please answer questions 1, 2 & 3 . Thank you!
MODULE 2 2. A sample of 20 bags of the same brand of candies was selected and found a mean weight of 120 grams. Assume that the population distribution of bag weights is normal. The weight of each bag was then recorded. The population standard deviation is known to be 2.1 grams. Construct a 90% confidence interval for the population mean weight of the candies. 3. A survey of 200 Internet users shows that they spend an average of 2 hours and 22 minutes per day on social networking. If the margin of error is 2.2 hours at 95% confidence, construct the confidence interval. 4. Suppose that a government law office does a study to determine the time needed to complete one personal profile sheet for consultation. It randomly surveys 100 people. The sample mean is 23.6 minutes. There is a known standard deviation of 7.0 minutes. The population distribution is assumed to be normal. Construct a 95% confidence interval for the population mean to complete the form. 5. A camp counselor is interested…
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.† Suppose a small group of 18 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with ? = 0.24 gram. (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) a. ? is known b. normal distribution of weights c. n is large d. uniform distribution of weights e. ? is unknown (c) Interpret your results in the context of this problem. a. We are 80% confident that the true average weight of Allen's hummingbirds falls within this interval. b. We are 20% confident that the true…
Given two independent random samples with the following results: n₂ = 8 x₂ = 124 $2 = 28 = 16 n₁ x₁ = 94 $1 = 16 Use this data to find the 90 % confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed. Copy Data Step 1 of 3: Find the point estimate that should be used in constructing the confidence interval.
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.† Suppose a small group of 11 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with σ = 0.28 gram. (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit-? upper limit-? margin of error-? (b) Find the sample size necessary for an 80% confidence level with a maximal margin of error E = 0.06 for the mean weights of the hummingbirds. (Round up to the nearest whole number.) _________hummingbirds
From a sample of 37 graduate students, the mean number of months of work experience prior to entering an MBA program was 36.63. The national standard deviation is known to be 19 months. What is a 90% confidence interval for the population mean? A 90% confidence interval for the population mean is 10 (Use ascending order. Round to two decimal places as needed.) ...
The birth weights of a sample of newborns were recorded for a group born to mothers who did not get regular prenatal care (Group 1) and for a group born to mothers who did (Group 2). A 93% confidence interval for 41 – 2 was computed as follows: (-2.12 pounds, -0.89 pounds) Interpret the endpoints of this interval in the context of this problem. Do not use the word "difference" in your answer.
An environmental health officer has been asked about levels of radon in homes in a particular county. As an initial step to forming a response to this inquiry, the officer plans to randomly select 20 homes in the county. The level of radon in each of the 20 homes will be measured, and the sample mean, x̅, and the sample standard deviation, s, will be calculated. Using these values, a 90% confidence interval will be constructed for the mean radon level for all homes in the county. Which of the following is the correct value of "t" for forming a confidence interval? a) 1.645 b) 1.328 c) 1.325 d) 1.725 e) 1.729