Group Condition n Sample mean, x Is Service 57 14.68 105.32 No Service 17 14.26 96.82
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A: the given values are M1=17.5 M2=22.7 SS1=100 SS2=124 n1=8 n2=8 S1=SS1n1-1 S1 = 1008-1 S1=3.8…
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Do college students who have volunteered for community service work differ from those who have not? A study obtained data from 57 students who had done service work and 17 who had not. One of the response variables was a measure of attachment to friends (roughly, secure relationships), measured by the Inventory of Parent and Peer Attachment. The results are summarized in the table below.
The 90% confidence interval for μ1−μ2 is:
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- A new postsurgical treatment is being compared with a standard treatment. Seven subjects receive the new treatment while seven others (the controls) receive the standard treatment. The recovery times in days are as follows: Treatment X 12 13 15 19 20 21 27 Control Y 18 23 24 30 32 35 40 calculate a 95% confidence interval for each set of data. Determine the error in the sample mean1 The results below are based on a sample of 20 employees selected to study the relationship between income (Y, in $1,000) and four variables: Age (X1, in years), work experience (X2,in years), number of years of education (X3), and number of past jobs (X4). Find the lower end point in a 90% confidence interval for the change in the mean salary in dollars, for a unit change in number of past jobs, assuming that the other predictors remain unchanged. Note that normality is assumed for the multiple regression model. Standard Coeffcient Error Intercept-9.611198 2.77988638 Age 1.327695 0.1149193 Experience -0.106705 0.14265559 7.311332 0,80324187 Educ PastJobs -0.504168 0.44771573 Type your numerical answer here. Numbera onlyA psychologist is studying the effects of lack of sleep on the performance of various perceptual-motor tasks. After a given period of sleep deprivation, a measurement of reaction time to an auditory stimulus was taken for each of 36 adult male subjects. The reaction times (in seconds) are summarized as follows:x = 1.82, S=0.22. Find a 99% confidence interval for the mean reaction time for sleep-deprived male subject
- Exercise has an impact on anxiety, but a team of researchers wanted to see if where people run makes a difference. They had N=8 people run in the lab and then later in the week run on a trail. The participants’ anxiety scores were measured after both sessions. Evaluate the results of her data using α = .052tail. **Attached Image** a. Show how the 95% confidence interval was calculated. b. State the conclusion in APA format.For the data set below, calculate r, r2, and a 95 percent confidence interval in r units. Then write a one- to two sentence conclusion statement that includes whether the null hypothesis was rejected or not and whether there is a strong /weak/no relationship. Assume a two tailed hypothesis and α = .05. Case 1 Case 2 Case 3 Case 4 Case 5 Case 6 X 1.05 1.15 1.30 2.00 1.75 1.00 Y 2 2 3 4 5 2A study of the amount of rainfall and the quantity of air pollution removed produced the following data: Daily Rainfall, x (0.01cm) Particulate Removed, y (µg/m³) 4.3 126 4.5 121 5.9 116 5.6 118 6.1 114 5.2 118 3.8 132 2.1 141 7.5 108 a. Find R? and r. b. Construct a 95% confidence interval for B1. Construct a 90% confidence interval for B,. c.
- In a sample of seven cars, each car was tested for nitrogen oxide emissions (in grams per mile). The results appear below. Assuming that nitrogen oxide emissions are normally distributed, 4. Car 1 2 3 4 5 6 7 Nitrogen oxide emission (g/mi) 0.13 0.18 0.15 0.09 0.12 0.18 0.08 a. Construct a 95% confidence interval for the mean amount of nitrogen oxide emissions for all cars. b. What effect would increasing the level of confidence have on the length of the interval?Use the given set of points to construct a 95% confidence interval for β1. No need to interpret the results. x 9 6 5 9 6 12 17 11 y 25 18 15 21 21 28 30 24A major company would like to assess the impact of using a professional trainer to conduct a confidence-building workshop with its salespeople. A sample of 16 workers is obtained. Half (n = 8) attend the workshop and the other half (n = 8) serve as a control group. Two weeks later, each of the participants is given a questionnaire measuring the level of self-confidence. The data are as follows: Controls Workshop M = 17.5 M = 22.7 SS = 100 SS = 124 What type of t-test would you have to conduct in this scenario? Are the data sufficient to conclude that the treatment has a significant effect? Use a two-tailed test with α = .05. State the hypothesis, find the critical region, calculate your test statistic, evaluate your hypothesis then calculate the Cohen’s d measure for this scenario. State whether this is a weak, moderate, or strong effect.
- A study compared tooth health and periodontal damage in a group of 40 young adult males with a tongue piercing and a control group of 50 young adult males without tongue piercing. Here are the summary statistics: Group Sample size Mean of enamel cracks StDev of enamel cracks Tongue piercing 40 4.1 3.7 No Tongue piercing 50 1.3 1.6 For the Tongue Piercing Group, find a 95% confidence interval for the mean of enamel cracks of young adult males with a tongue piercing. Interpret your interval with the context. Which method will you use here to find you interval? 1-sample T interval 2-sample T interval 2-sample Z test. 2-proportion Z test Interpret your interval with the context.you conducted additional studies with these men and found the following: a. The RR for those who drank one drink per day was 1.50 (95% CI:1.32-1.67) in comparison to the abstainers. b. For those men who drank three or more drinks per day the RR compared to the abstainers was 4.20 (95% CI 2.68-5.85). Question: We can tell from the Confidence Intervals provided in #7 whether there are likely more people in the “one drink a day” group or the “3+ drinks per day” group. Which one likely has more people and how can we tell?It is hard to persuade consumers to abandon a product with which they are familiar. One experiment gave consumers free samples of new laundry detergent and also a standard detergent. After some time, ask the subjects which detergent they prefer. Here are the data. User Nonuser Prefer new product 19 31 Prefer standard product 29 27 a. Calculate a 90% confidence interval for the difference in proportions between nonusers and users of the standard detergent that prefer the new detergent. b. Based on the confidence interval in (a), can we conclude that a significant difference exists between the proportion of nonusers of the standard detergent who prefer the new detergent and the proportion of users of the standard detergent who prefer the new detergent? Explain.