An arctic weather balloon is filled with 37.5 L of helium gas inside a prep shed. The temperature inside the shed is 6. °C. The balloon is then taken outside, where the temperature is -31. °C. Calculate the new volume of the balloon.
An arctic weather balloon is filled with 37.5 L of helium gas inside a prep shed. The temperature inside the shed is 6. °C. The balloon is then taken outside, where the temperature is -31. °C. Calculate the new volume of the balloon.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Problem: Calculating the New Volume of a Helium Balloon
An arctic weather balloon is initially filled with 37.5 L of helium gas inside a preparation shed. The initial temperature inside the shed is 6°C. The balloon is then taken outside, where the temperature drops to -31°C. Determine the new volume of the balloon.
Assumption:
- The pressure on the balloon remains constant at exactly 1 atm.
Approach:
- Use Charles's Law which states that \( \frac{V_1}{T_1} = \frac{V_2}{T_2} \), where V is volume and T is temperature in Kelvin.
Instructions:
- Convert the given temperatures from Celsius to Kelvin.
- Apply Charles's Law to solve for the new volume \( V_2 \).
- Present your answer rounded to 3 significant digits.
### Conversion of Temperatures:
- Initial Temperature \( T_1 \): \( 6°C = 279 \, \text{K} \)
- Final Temperature \( T_2 \): \( -31°C = 242 \, \text{K} \)
### Calculation:
Given:
\( V_1 = 37.5 \, \text{L} \), \( T_1 = 279 \, \text{K} \), \( T_2 = 242 \, \text{K} \)
Using Charles's Law:
\[ \frac{37.5}{279} = \frac{V_2}{242} \]
Solve for \( V_2 \):
\[ V_2 = \frac{37.5 \times 242}{279} \]
### New Volume \( V_2 \):
Calculate the expression to find the approximate volume, rounding to 3 significant digits.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9ac4fab7-4126-49f3-8d16-60074d8271b3%2F5c23ced5-528a-4b98-b5cc-800af7f7e4b1%2F8dk3pq_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem: Calculating the New Volume of a Helium Balloon
An arctic weather balloon is initially filled with 37.5 L of helium gas inside a preparation shed. The initial temperature inside the shed is 6°C. The balloon is then taken outside, where the temperature drops to -31°C. Determine the new volume of the balloon.
Assumption:
- The pressure on the balloon remains constant at exactly 1 atm.
Approach:
- Use Charles's Law which states that \( \frac{V_1}{T_1} = \frac{V_2}{T_2} \), where V is volume and T is temperature in Kelvin.
Instructions:
- Convert the given temperatures from Celsius to Kelvin.
- Apply Charles's Law to solve for the new volume \( V_2 \).
- Present your answer rounded to 3 significant digits.
### Conversion of Temperatures:
- Initial Temperature \( T_1 \): \( 6°C = 279 \, \text{K} \)
- Final Temperature \( T_2 \): \( -31°C = 242 \, \text{K} \)
### Calculation:
Given:
\( V_1 = 37.5 \, \text{L} \), \( T_1 = 279 \, \text{K} \), \( T_2 = 242 \, \text{K} \)
Using Charles's Law:
\[ \frac{37.5}{279} = \frac{V_2}{242} \]
Solve for \( V_2 \):
\[ V_2 = \frac{37.5 \times 242}{279} \]
### New Volume \( V_2 \):
Calculate the expression to find the approximate volume, rounding to 3 significant digits.

Transcribed Image Text:The vapor pressure of methanol at 25 °C is 126. torr. Calculate the vapor pressure in mmHg and atm. Round each of your answers to 3 significant digits.
Box for "mmHg" and "atm" values.
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