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Calculations eqpt = equilvalent point ☆ PHeqpt = 7.98 Vegpt =19.95mL Vrop = Veapt Veget= ☆ bP= boiling point ☆ ☆ mass = 0.300g☆ 19.95 = 9.97 2 pka bp (PH 6p) = 10.09348) (9.97) +2.289 = 3.22 Mbase = 0.1002 M Vase = 19.95mL x- 1000mL mol pase =0.1002M × 19.95mL x IL molar mass = mass mol mol = mass molar mass 1000 mL

Calculations eqpt = equilvalent point ☆ PHeqpt = 7.98 Vegpt =19.95mL Vrop = Veapt Veget= ☆ bP= boiling point ☆ ☆ mass = 0.300g☆ 19.95 = 9.97 2 pka bp (PH 6p) = 10.09348) (9.97) +2.289 = 3.22 Mbase = 0.1002 M Vase = 19.95mL x- 1000mL mol pase =0.1002M × 19.95mL x IL molar mass = mass mol mol = mass molar mass 1000 mL

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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With the image attached please do the calculations/calculate what is highlighted in yellow please Please also calculate - percent % error in molar mass - percent % error in pKa Please please please answer as fast as possible
Calculations eqpt = equilvalent point ☆ ☆eapt= PHeqpt = 7.98 Vegpt =19.95mL ☆ bP= boiling point ☆ ☆ mass = 0.300g * Vop = Vege+ -19.95 = 9.97 2. 2 Pkap (PH)=(0.09348) (9.97) +2.289 = 3.22 Mbase = 0.1002 M Vase=19.95 mL x- 1000mL mol pase = 0.1002M x 19.95mL x IL 1000 mL molar mass = mass mol mol = mass molar mass 11
Transcribed Image Text:Calculations eqpt = equilvalent point ☆ ☆eapt= PHeqpt = 7.98 Vegpt =19.95mL ☆ bP= boiling point ☆ ☆ mass = 0.300g * Vop = Vege+ -19.95 = 9.97 2. 2 Pkap (PH)=(0.09348) (9.97) +2.289 = 3.22 Mbase = 0.1002 M Vase=19.95 mL x- 1000mL mol pase = 0.1002M x 19.95mL x IL 1000 mL molar mass = mass mol mol = mass molar mass 11
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