LOD秀寸怀 /%D4000тр3000200015001000500波数/cm²3398 663073 723065 743047 743011 742947 702929 622854 741440 641203 68629 771712 41611 441600 671589 601474 641433 571175 6B824 771405 7413981149 64761 35701101 79671 721328 551088 70566 721277 411035 58560 741463 6D1244 681014 7D466 60 Please interpret this IR for me.LOD秀寸怀 /%D4000งс3000200015001000500波数/cm²3398 663073 72742864 741712 416111440 641433 571203691175 6B44741600 671589 60140513981328 55741149 64701101791088 70701474 64 1277 411035582929621463 6D 1244681014 7D3063I of30473011 742947629 77824 77761 35671 72566 72560 74466 60

Please interpret this IR for me. LO0 D 4000 S C 3000 2000 1500 1000 500 波数/cm² 3398 66 3073 72 2864 74 1440 64 1203 63 829 77 1712 4 1433 57 1175 6B 824 77 3063 74 1611 44 1405 74 1149 64 761 35 3047 74 1600 67 1398 70 1101 79 671 72 3011 74 1589 60 2947 2929 62 70 1474 64 1463 60 1328 55 1277 41 1244 68 1088 70 566 72 1035 1014 70 58 560 74 466 60

Please interpret this IR for me. LO0 D 4000 S C 3000 2000 1500 1000 500 波数/cm² 3398 66 3073 72 2864 74 1440 64 1203 63 829 77 1712 4 1433 57 1175 6B 824 77 3063 74 1611 44 1405 74 1149 64 761 35 3047 74 1600 67 1398 70 1101 79 671 72 3011 74 1589 60 2947 2929 62 70 1474 64 1463 60 1328 55 1277 41 1244 68 1088 70 566 72 1035 1014 70 58 560 74 466 60

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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100 98- 96- 94- 92- 90- 88- 86- 84- 82- 80- 78- 76+ 4000 3533 PAR 3500 3402.5 3002.41cm-1 2916.20cm-1 3000 2500 cm-1 2000 1652.35cm-1 1750 6 1313.35cm-1 1500 1387.57cm-1 1363.15cm-1 1220.86cm-1 1271.72cm-1 1135.71cm-1 1111.39cm-1 1196.92cm-1 1075.30cm 1247.21dm-1 1067.26cm-1 987.91cm-1 1000 820.06cm-1 720.37cm-1 1023.11cm-1 1043.87cm-1 869.18cm-1 591.82gm-1 754.10cm-1 677.07cm-M 494.180m/1 408.17cm-1 420.01cm-1 471.14cm-1 627.86cm-1 446.95cm-1 564.12cm-1 500 400
What are the Lineear Measurements of: G. H.
Q 1 thank you!
Consider the reaction described by the equation C₂H₂Br₂ (aq) + 31¯¯(aq) · C₂H₂(g) + 2 Br¯(aq) + I₂ (aq) The rate law is rate = k[C₂H₂Br₂][I] where k = 0.00475 M-¹. s-¹. S What are the missing entries in the table? Run [C₂H₂Br₂lo (M) [Ilo (M) 1 0.249 2 3 X 0.249 0.249 y 0.249 Initial rate of formation of C₂H₂ (M-s¯¹) 0.00118 0.000589 Z
Solving for a variable in terms of other variables using addition... Solve for n. 5m +9n=d n = DO %3D
I need help with this general chemistry questions please.
Table 3: Data for Trial 1 Water displaced in mL Time (seconds) 2 mL 49 4 mL 84 6 mL 116 8 mL 145 10 mL 174 12 mL 202 14 mL 230 16 mL 253 18 mL 280 20 mL 313 22 mL 350 Table 4: Data for Trial 2 Water displaced in mL Time (seconds) 2 mL 78 4 mL 144 6 mL 175 8 mL 205 10 mL 255 12 mL 308 14 mL 330 16 mL 409 18 mL 463 20 mL 515 22 mL 575 Table 5: Data for Trial 3 Water displaced in mL Time (seconds) 2 mL 53 4 mL 100 6 mL 139 8 mL 178 10 mL 213 12 mL 247 14 mL 282 16 mL 319 18 mL 363 20 mL 412 22 mL 463 Help me with this part Trial 1 (Table 3) Slope ______________________ Reciprocal Slope _______________ Trial 2 (Table 4) Slope _______________________ Reciprocal Slope ________________…
L=0, what is TRUE n=6 Ml=-1 Ml=1 Ms=1 Ms=0
X + u.co X search 4.213 x 10-³ 0.1 Your Aktiv Learning trial expires on 08/29/22 at 07:08 PM A hot air balloon's gondola is suspended below a cloth envelope containing 4.213 x 10 liters of hot air. How many milliliters of hot air this? 10⁰ 10⁰ O Bi 10 Question 61 of 73 4.213 x 10³ 0.01 4.213 4.213 x 10° 4.213 x 10-⁰ L H ml. O 0.001 4.213 x 10⁰ 4.213 x 10° 1000 1 4.213 x 10° 100 ها
A method of analysis yields masses of gold that are low by 0.4 mg. This method is used for analysis of ores that assay about 3.1% gold. What minimum sample mass should be taken if the relative error resulting from a 0.4-mg loss is not to exceed a. -0.1%? Mass = b. -0.4%? Mass = 6. C. -0.8%? Mass = %3D d. -1.1%? Mass =
Part D [OH ] = 4.0x10-11 M Express your answer using two decimal places. ? pH = Submit Request Answer Part E [H3O*] = 6.5x10-8 M Express your answer using two decimal places. V ΑΣφ pH %3D Suhmit Request Answer
編輯顯示方式瀏覽記錄書籤輔助說明視窗 62%D 週日下午11:23 A access4.lon-capa.illinois.edu ssignments C. LON-CAPA Prelab 5 General Chemistry Labs: Dilutions... Assignments-Fall 2019-GEOG 21.. Week 7- October 10-Fall 2019-G Course: ESL 111 B FA19: Intro to Ac... The stock solutions in Lab 5 were made as follows: Chemical formula mass of dye volume of solution Color Name FD&C Blue 1 Erioglaucine C37H 34 N2 Na2Og S3 0.06343 g 1.000 L C16H9N4NA309S2 0.1860 g FD&C Yellow 5 Tartrazine 1.000 L For each of the dyes you will carry out the following dilution scheme: 2.50 mL of stock +22.50 mL water Dilution #1 Dilution #2 15.00 mL of #1 + 10.00 mL water Dilution #3 = 17.50 mL of #2 + 7.50 mL water )mt Dilution #4 = 15.00 mE of #3 + 10.00 mL water Determine the concentrations of the stock solutions and the four dilutions and enter them into the tables below. Pay attention to the number of significant figures for each calculation and be sure to enter your answer to the correct number of significant figures. Not all…