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A method of analysis yields masses of gold that are low by 0.4 mg. This method is used for analysis of ores that assay about 3.1% gold. What minimum sample mass should be taken if the relative error resulting from a 0.4-mg loss is not to exceed a. -0.1%? Mass = b. -0.4%? Mass = 6. C. -0.8%? Mass = %3D d. -1.1%? Mass =

A method of analysis yields masses of gold that are low by 0.4 mg. This method is used for analysis of ores that assay about 3.1% gold. What minimum sample mass should be taken if the relative error resulting from a 0.4-mg loss is not to exceed a. -0.1%? Mass = b. -0.4%? Mass = 6. C. -0.8%? Mass = %3D d. -1.1%? Mass =

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Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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A method of analysis yields masses of gold that are low by 0.4 mg. This method is used for analysis of ores that assay about 3.1% gold. What minimum sample mass should be taken if the relative error resulting from a 0.4-mg loss is not to exceed a. -0.1%? Mass = b. -0.4%? Mass = 6. C. -0.8%? Mass = %3D d. -1.1%? Mass =
Transcribed Image Text:A method of analysis yields masses of gold that are low by 0.4 mg. This method is used for analysis of ores that assay about 3.1% gold. What minimum sample mass should be taken if the relative error resulting from a 0.4-mg loss is not to exceed a. -0.1%? Mass = b. -0.4%? Mass = 6. C. -0.8%? Mass = %3D d. -1.1%? Mass =
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The relative error is (mass loss/Total mass )x 100.

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