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Was your average experimental mass percent of oxygen in potassium chlorate higher or lower than the theoretical value (circle one)? Higher Lower Which of the following sources of error could be used to explain this discrepancy (circle one)? A. The potassium chlorate sample was not heated strongly or long enough. B. Some of the potassium chloride product splattered out of the crucible during the heating process. Explain your choice. Your response should include an analysis of the calculations you performed with your caw data to obtain your experimental % of oxygen.

Was your average experimental mass percent of oxygen in potassium chlorate higher or lower than the theoretical value (circle one)? Higher Lower Which of the following sources of error could be used to explain this discrepancy (circle one)? A. The potassium chlorate sample was not heated strongly or long enough. B. Some of the potassium chloride product splattered out of the crucible during the heating process. Explain your choice. Your response should include an analysis of the calculations you performed with your caw data to obtain your experimental % of oxygen.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Give explanation and use the calculations in the second image.

Was your average experimental mass percent of oxygen in potassium chlorate higher or lower than the theoretical value (circle one)? Higher Lower Which of the following sources of error could be used to explain this discrepancy (circle one)? A. The potassium chlorate sample was not heated strongly or long enough. B. Some of the potassium chloride product splattered out of the crucible during the heating process. Explain your choice. Your response should include an analysis of the calculations you performed with raw data to obtain your experimental % of oxygen. your
Transcribed Image Text:Was your average experimental mass percent of oxygen in potassium chlorate higher or lower than the theoretical value (circle one)? Higher Lower Which of the following sources of error could be used to explain this discrepancy (circle one)? A. The potassium chlorate sample was not heated strongly or long enough. B. Some of the potassium chloride product splattered out of the crucible during the heating process. Explain your choice. Your response should include an analysis of the calculations you performed with raw data to obtain your experimental % of oxygen. your
Mass of original KClO3 sample= Mass of KCl residue = Mass of Oxygen released = Mass Percent of Oxygen in KC103 Average Mass Percent Oxygen = -KCIO3] - Sample 1 [Mass of crucible, lid + [Mass of crucible + lid] = 33.745 g - 32.721 g = 1.024 g [Mass of crucible, lid + residue after 2nd heating] - [Mass of crucible + lid] = 33.314 g - 32.721 g = 0.593 g Mass of original KCIO3 sample - Mass of KCI residue = 1.024 g - 0.593 g = 0.431 g 42.090 +39.444 2 Mass Percent of Oxygen (experim-Mass Percent of Oxygen (experim- ental) = Mass of Oxygen released /ental) = Mass of Oxygen released Mass of Potassium chlorate used x Mass of Potassium chlorate used x 100 = 0.431 g / 1.024 g x 100 = 100 = 0.383 g / 0.971 g x 100 = 42.090 % 39.444% 81.534 Sample 2 [Mass of crucible, lid + KCIO3] - [Mass of crucible + lid] = 33.692 g - 32.721 g = 0.971 g 2 [Mass of crucible, lid + residue after 2nd heating] - [Mass of crucible + lid] = 33.309 g - 32.721 g = 0.588 g Mass of original KCIO3 sample - Mass of KCI residue= 0.971 g - 0.588 g = 0.383 g = 40.767 %
Transcribed Image Text:Mass of original KClO3 sample= Mass of KCl residue = Mass of Oxygen released = Mass Percent of Oxygen in KC103 Average Mass Percent Oxygen = -KCIO3] - Sample 1 [Mass of crucible, lid + [Mass of crucible + lid] = 33.745 g - 32.721 g = 1.024 g [Mass of crucible, lid + residue after 2nd heating] - [Mass of crucible + lid] = 33.314 g - 32.721 g = 0.593 g Mass of original KCIO3 sample - Mass of KCI residue = 1.024 g - 0.593 g = 0.431 g 42.090 +39.444 2 Mass Percent of Oxygen (experim-Mass Percent of Oxygen (experim- ental) = Mass of Oxygen released /ental) = Mass of Oxygen released Mass of Potassium chlorate used x Mass of Potassium chlorate used x 100 = 0.431 g / 1.024 g x 100 = 100 = 0.383 g / 0.971 g x 100 = 42.090 % 39.444% 81.534 Sample 2 [Mass of crucible, lid + KCIO3] - [Mass of crucible + lid] = 33.692 g - 32.721 g = 0.971 g 2 [Mass of crucible, lid + residue after 2nd heating] - [Mass of crucible + lid] = 33.309 g - 32.721 g = 0.588 g Mass of original KCIO3 sample - Mass of KCI residue= 0.971 g - 0.588 g = 0.383 g = 40.767 %
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