ADD R3 = R4 + R9; I4: lw $R1,0($R3) //LDW R1 = MEM[R3 + 0]; I5: sub $R3,$R1,$R4 //SUB R3 = R1 -
Consider the following assembly language code:
I0: add $R4,$R1,$R0 //ADD R4 = R1 + R0;
I1: lw $R1,100($R3) //LDW R1 = MEM[R3 + 100];
I2: lw $R9,4,($R1) // LDW R9 = MEM[R1 + 4];
I3: add $R3,$R4,$R9 //ADD R3 = R4 + R9;
I4: lw $R1,0($R3) //LDW R1 = MEM[R3 + 0];
I5: sub $R3,$R1,$R4 //SUB R3 = R1 - R4;
I6: and $R9,$R9,$R7 //AND R9 = R9 & R7;
I7: sw $R2,100($R4) //STW MEM[R4 + 100] = R2;
I8: and $R4,$R2,$R1 //AND R4 = R2 & R1;
I9: add $R1,$R5,$R4 //ADD R1 = R5 + R4;
Assume that the code runs in a pipeline with the same five stages, but the forwarding
There is a total of ____ cycles
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