• AbsoluteRegister indirect• Based (base + displacement)• Scale indexed (base + index × constant)• Memory indirect• Auto increment/decrement (by 1 byte)Consider the following high-level programs:uint8_t a[150]; // a is allocated in memoryfor (i = 0; i < 150; i++) {a[i] = 5;}• int a [150];for (i = 0; i < 150; i++) {a[i]5;// a is allocated in memory}int *p; // *p is allocated in memory*p = 150;• int **p; // *p and **p are allocated in memory**P = 150;Assume that in the first two programs, a register contains the address of the start of thearray, and in the last two programs, a register contains the value of p. For each of theabove four programs, which of the addressing modes, do you think, would lead to theminimum number of instructions? (Note that no addressing mode fits perfectly. Youmight require other instructions for address computation.)

Addressing modes in computer architecture dictate how the address of an operand is calculated.…

Answered: Consider the following high-level…

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Consider the following high-level programs: uint8_t a[150]; // a is allocated in memory for (i = 0; i < 150; i++) {

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Question

• Absolute
Register indirect
• Based (base + displacement)
• Scale indexed (base + index × constant)
• Memory indirect
• Auto increment/decrement (by 1 byte)
Consider the following high-level programs:
uint8_t a[150]; // a is allocated in memory
for (i = 0; i < 150; i++) {
a[i] = 5;
}
• int a [150];
for (i = 0; i < 150; i++) {
a[i]
5;
// a is allocated in memory
}
int *p; // *p is allocated in memory
*p = 150;
• int **p; // *p and **p are allocated in memory
**P = 150;
Assume that in the first two programs, a register contains the address of the start of the
array, and in the last two programs, a register contains the value of p. For each of the
above four programs, which of the addressing modes, do you think, would lead to the
minimum number of instructions? (Note that no addressing mode fits perfectly. You
might require other instructions for address computation.)

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