Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a comma (no spaces). Ex: If origList = {4, 5, 10, 12} and offsetAmount = {2, 4, 7, 3}, print: 6,9,17,15, #include #include using namespace std; int main() { const int NUM_VALS = 4; int origList[NUM_VALS]; int offsetAmount[NUM_VALS]; int i; cin >> origList[0]; cin >> origList[1]; cin >> origList[2]; cin >> origList[3]; cin >> offsetAmount[0]; cin >> offsetAmount[1]; cin >> offsetAmount[2]; cin >> offsetAmount[3]; /* Your code goes here */ cout << endl; return 0

Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a comma (no spaces). Ex: If origList = {4, 5, 10, 12} and offsetAmount = {2, 4, 7, 3}, print: 6,9,17,15, #include #include using namespace std; int main() { const int NUM_VALS = 4; int origList[NUM_VALS]; int offsetAmount[NUM_VALS]; int i; cin >> origList[0]; cin >> origList[1]; cin >> origList[2]; cin >> origList[3]; cin >> offsetAmount[0]; cin >> offsetAmount[1]; cin >> offsetAmount[2]; cin >> offsetAmount[3]; /* Your code goes here */ cout << endl; return 0

EBK JAVA PROGRAMMING

9th Edition

ISBN:9781337671385

Author:FARRELL

Publisher:FARRELL

Chapter8: Arrays

Section: Chapter Questions

Problem 9PE

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5.13 LAB: Output numbers in reverse

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Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a space. Ex: If origList = {40, 50, 60, 70} and offsetAmount = {5, 7, 3, 0}, print: 45 57 63 70 #include <iostream>#include <vector>using namespace std; int main() {const int NUM_VALS = 4;vector<int> origList(NUM_VALS);vector<int> offsetAmount(NUM_VALS);unsigned int i; for (i = 0; i < origList.size(); ++i) {cin >> origList.at(i);} for (i = 0; i < offsetAmount.size(); ++i) {cin >> offsetAmount.at(i);} cout << endl; return 0;} Please help me with this problem using c++.
Language is C++
For any element in keysList with a value greater than 50, print the corresponding value in itemsList, followed by a comma (no spaces). Ex: If the input is: 32 105 101 35 10 20 30 40 the output is: 20,30, 1 #include 2 3 int main(void) { const int SIZE_LIST = 4; int keysList[SIZE_LIST]; int itemsList[SIZE_LIST]; int i; 4 6 7 8 scanf("%d", &keysList[0]); scanf ("%d", &keysList[1]); scanf("%d", &keysList[2]); scanf("%d", &keysList[3]); 10 11 12 13 scanf ("%d", &itemsList[0]); scanf ("%d", &itemsList[1]); scanf("%d", &itemsList[2]); scanf ("%d", &itemsList[3]); 14 15 16 17 18 19 /* Your code goes here */ 20 21 printf("\n"); 22 23 return 0; 24 }
В.width; } { t = B.type; w = { T.type = C.type; T.width = C.width; } T → B C В > int { B.type = integer; B.width 4; } В — foat { B.type = float; B.width = 8; } { C.type = t; C.width = w; } C - [ num] C1 = array(num. value, C1.type); { C.type C.width = num. value x C1. width; }
ion C Lons Employee -id: int -name String - dob : Date -staff : ArrayList +setid(int): void +getld() : int +setName(String): void +setDob(Date) : void +getDob(): Date +addStaff(Employee) : void +getStaff() : ArrayList
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Subtract each element in origList with the corresponding value in offsetAmount. Print each difference followed by a space. Ex: If origList = {4, 5, 10, 12} and offsetAmount = {2, 4, 7, 3}, print: 2 1 3 9 #include <iostream>#include <string.h>using namespace std; int main() { const int NUM_VALS = 4; int origList[NUM_VALS]; int offsetAmount[NUM_VALS]; int i; cin >> origList[0]; cin >> origList[1]; cin >> origList[2]; cin >> origList[3]; cin >> offsetAmount[0]; cin >> offsetAmount[1]; cin >> offsetAmount[2]; cin >> offsetAmount[3]; /* Your code goes here */ cout << endl; return 0;}
Write the statement that declares and instantiates an array of type double using the identifier temperatures that will hold 30 values. Edit View Insert Format Tools Table 12pt v Paragraph v :
Assign pizzasInStore's first element's numCalories with the value in pizzasInStore's second element's numCalories. #include <stdio.h>#include <string.h> typedef struct Pizza_struct { char pizzaName[75]; int numCalories;} Pizza; int main(void) { Pizza pizzasInStore[2]; scanf("%s", pizzasInStore[0].pizzaName); scanf("%d", &pizzasInStore[0].numCalories); scanf("%s", pizzasInStore[1].pizzaName); scanf("%d", &pizzasInStore[1].numCalories); /* Your code goes here */ printf("A %s slice contains %d calories.\n", pizzasInStore[0].pizzaName, pizzasInStore[0].numCalories); printf("A %s slice contains %d calories.\n", pizzasInStore[1].pizzaName, pizzasInStore[1].numCalories); return 0;} I tried 10 time but I cant solve it so please help me
javascript Define a function, myIncludes, that accepts two parameters: an array and a searchValue. myIncludes should return true if the searchValue is an element in the array. Otherwise, myIncludes should return false. example myIncludes([10, 20, 30], 20); // => true myIncludes(['apples', 'bananas', 'citrus'], 'pears'); // => false
Double any element's value that is less than minValue. Ex: If minValue = 10, then dataPoints = {2, 12, 9, 20} becomes {4, 12, 18, 20}. #include <iostream>using namespace std; int main() {const int NUM_POINTS = 4;int dataPoints[NUM_POINTS];int minValue;int i; cin >> minValue; for (i = 0; i < NUM_POINTS; ++i) {cin >> dataPoints[i];} /* Your solution goes here */ for (i = 0; i < NUM_POINTS; ++i) {cout << dataPoints[i] << " " ;}cout << endl; return 0;} Please help me with this problem using c++.