For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If keysList={42, 105, 101, 100) and itemsList={10, 20, 30, 40), print: 20 30 Since keysList.at(1) and keysList.at(2) have values greater than 100, the value of itemsList.at(1) and itemsList.at(2) are printed. Code writing challenge activity demo 464730 3214874 qx3zqy7 5 int main() { 6 7 8 SAHARATSISAANN 9 10 11 12 14 13 } 16 17 15 for (i = 0; i < itemsList.size(); ++i) { cin >> itemsList.at(i); 18 19 29 const int SIZE_LIST = 4; 21 vector keysList (SIZE_LIST); vector itemsList (SIZE_LIST); unsigned int i; 22 for (i = 0; i < keysList.size(); ++i) { cin >> keysList.at (i); } V* Your solution goes here */ cerned with CamScanner
For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If keysList={42, 105, 101, 100) and itemsList={10, 20, 30, 40), print: 20 30 Since keysList.at(1) and keysList.at(2) have values greater than 100, the value of itemsList.at(1) and itemsList.at(2) are printed. Code writing challenge activity demo 464730 3214874 qx3zqy7 5 int main() { 6 7 8 SAHARATSISAANN 9 10 11 12 14 13 } 16 17 15 for (i = 0; i < itemsList.size(); ++i) { cin >> itemsList.at(i); 18 19 29 const int SIZE_LIST = 4; 21 vector keysList (SIZE_LIST); vector itemsList (SIZE_LIST); unsigned int i; 22 for (i = 0; i < keysList.size(); ++i) { cin >> keysList.at (i); } V* Your solution goes here */ cerned with CamScanner
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
C++
![For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If
keysList={42, 105, 101, 100) and itemsList={10, 20, 30, 40), print:
20 30
Since keysList.at(1) and keysList.at (2) have values greater than 100, the value of itemsList.at(1) and itemsList.at (2) are printed.
Code writing challenge activity demo
464730.3214874 qx3zqy7
5 int main() {
6
7 vector<int> keysList (SIZE_LIST);
8 vector<int> itemsList (SIZE_LIST);
9
unsigned int i;
10
11
12
13
14
15
16
17
18
const int SIZE_LIST = 4;
for (i = 0; i < keysList.size(); ++i) {
cin >> keysList.at (i);
}
for (i = 0; i < itemsList.size(); ++i) {
cin >> itemsList.at (i);
}
19
V* Your solution goes here */
29
2 canner with CamScanner
<< endl;
22
A](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff8c67d92-2376-430d-971a-91f6c41cd4dc%2F8c568279-50d5-4528-bcd8-ac4bfa689895%2Fa6hll32_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If
keysList={42, 105, 101, 100) and itemsList={10, 20, 30, 40), print:
20 30
Since keysList.at(1) and keysList.at (2) have values greater than 100, the value of itemsList.at(1) and itemsList.at (2) are printed.
Code writing challenge activity demo
464730.3214874 qx3zqy7
5 int main() {
6
7 vector<int> keysList (SIZE_LIST);
8 vector<int> itemsList (SIZE_LIST);
9
unsigned int i;
10
11
12
13
14
15
16
17
18
const int SIZE_LIST = 4;
for (i = 0; i < keysList.size(); ++i) {
cin >> keysList.at (i);
}
for (i = 0; i < itemsList.size(); ++i) {
cin >> itemsList.at (i);
}
19
V* Your solution goes here */
29
2 canner with CamScanner
<< endl;
22
A
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