Answered: flip_matrix(mat:list)->list You will be…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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flip_matrix(mat:list)->list You will be given a single parameter a 2D list (A list with lists within it) this will look like a 2D matrix when printed out, see examples below. Your job is to flip the matrix on its horizontal axis. In other words, flip the matrix horizontally so that the bottom is at top and the top is at the bottom. Return the flipped matrix. To print the matrix to the console: print('\n'.join([''.join(['{:4}'.format(item) for item in row]) for row in mat])) Example: Matrix: W R I T X H D R L G L K F M V G I S T C W N M N F Expected: W N M N F G I S T C L K F M V H D R L G W R I T X Matrix: L C S P Expected: S P L C Matrix: A D J A Q H J C I Expected: J C I A Q H A D J

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# This function will reverse a number
def reverse_number(num):
   rev_num = 0
   # Iterate until num becomes 0
   while num!=0:
       # Reversing from end
       rev_num = rev_num*10 + num%10
       # Reduce num
       num = num//10
   # Return the reversed number
   return rev_num

def reverse_number_in_list(number_list):
   new_list = []
   # For each number in number_list
   for num in number_list:
       # Reverse the number and append output to new_list
       new_list.append(reverse_number(num))
   # Return new_list
   return new_list

# Function calling and printing output
print(reverse_number_in_list([13, 45, 690, 57]))

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