Answered: Return the index of the first integer…

Return the index of the first integer in items that is less than its index, or -1 if no such integer exists in items. >>> small_index([2, 5, 7, 99, 6]) -1

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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class SpecialList: """A list that can hold a limited number of items.""" def __init__(self, size: int) -> None: """Initialize this special list to hold at most size items. >>> L = SpecialList(10) >>> L.size 10 >>> L.value_list [] """ # complete the code def push_value(self, new_value: object) -> None: """Append new_value to this list, if there is enough space in the list according to its maximum size. If there is insufficient space, new_value should not be added to the list. >>> L = SpecialList(2) >>> L.push_value(3) >>> L.push_value(4) >>> L.push_value(5) >>> L.value_list [3, 4] """ # complete the code def pop_most_recent_value(self) -> object: """Return the value added most recently to value_list and remove it from the list.…
C++ code Screenshot and output is must
# cannot contain syntax error # stack class class Stack:def __init__(self, iL=[]):self.aList = iL[:] def push(self, newElem:int):"""push a new element on top"""self.aList.append(newElem) def pop(self)->int:"""return top item"""return self.aList.pop() def empty(self):"""Is the stack empty?"""return self.aList == [] def __repr__(self):return repr(self.aList) # use only the above stack methods to define a function to# delete an item x from a stack, (only one x (the upper one) is to be deleted)# keep the order of the remaining items in the stack unchanged# can change orginal stack# return a new stack def delx(sk:Stack, x:'item')-> Stack: #Code goes here if __name__ == "__main__": #Testing code here
#include <stdio.h> int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key); int *joinArray(int arrA[], int arrB[]) { int j = 0; if ((arrB[0] + arrB[4]) % 5 == 0) { arrB[0] = 0; arrB[4] = 0; } for (int i = 0; i < 5; i++) { arrC[j++] = arrA[i]; if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1)) { continue; } else arrC[j++] = arrB[i]; } for (int i = 0; i < j; i++) { int temp; for (int k = i + 1; k < j; k++) { if (arrC[i] > arrC[k]) { temp = arrC[i]; arrC[i] = arrC[k]; arrC[k] = temp; } } } for (int i = 0; i < j; i++) { printf("%d ", arrC[i]); } return arrC; } int bSearch(int arr[], int l, int h, int key) { if (h >= l) { int mid = l + (h - l) / 2; if…
Incoroporate or use below code as reference #include <stdio.h>#include <stdlib.h>#include <time.h> typedef struct node_struct {int item;struct node_struct *next;} node; /*** 10->NULL* We want to insert 20* First call ([10], 20) [has not finished yet]* {10, {20, NULL}}*** Second call (NULL, 20) {20, NULL}*/node* insert_unordered(node *temp_root, int item) {if (temp_root == NULL) {temp_root = malloc(sizeof(node));temp_root->item = item;temp_root->next = NULL;} else {temp_root->next = insert_unordered(temp_root->next, item);}return temp_root;} /*** This is atypical linked list because* (i) it does not allow duplicates and* (ii) it is sorted* 10->20, i want to insert 15* 10->15->20**/
int X[10]={2,0,6,11,4,5,9,11,-2,-1); From the code above, what is the value of X[8] ?
#include <iostream> using namespace std; const int ROWS = 10; const int COLS = 10; int generateRND(int MIN, int MAX) { return rand() % (MAX - MIN + 1) + MIN; } void initializeArray(int C[][COLS], int min, int max) { for (size_t i = 0; i < ROWS; i++) { for (size_t j = 0; j < COLS; j++) { C[i][j] = generateRND(min, max); } } } void swap(int A[][COLS], int B[][COLS]) { int temp; for (size_t j = 0; j < COLS; j += 2) { for (size_t j = 0 ; j< COLS; j +=) } } void printArray(int C[][COLS]) { for (size_t i = 0; i < ROWS; i++) { for (size_t j = 0; j < COLS; j++) { cout << C[i][j] << " "; } cout << endl; } } int main() { srand((unsigned)time(0)); int A[ROWS][COLS] = { 0 }; int B[ROWS][COLS] = { 0 }; const int MIN = 2; const int MAX = 50; initializeArray(A, 2, 50); } Declares two 10X10 Two-dimensional arrays A and B of type integer. Each array consists of 100 random integers between 2 and 50. 1.       Swaps (exchange) the elements of A with…
class BinaryImage:     def __init__(self):         pass     def compute_histogram(self, image):         """Computes the histogram of the input image         takes as input:         image: a grey scale image         returns a histogram as a list"""         hist = [0]*256         return hist     def find_otsu_threshold(self, hist):         """analyses a histogram it to find the otsu's threshold assuming that the input hstogram is bimodal histogram         takes as input         hist: a bimodal histogram         returns: an optimal threshold value (otsu's threshold)"""         threshold = 0         return threshold     def binarize(self, image):         """Comptues the binary image of the the input image based on histogram analysis and thresholding         take as input         image: an grey scale image         returns: a binary image"""         bin_img = image.copy()         return…
dictionaries = [] dictionaries.append({"First":"Bob", "Last":"Jones"}) dictionaries.append({"First":"Harpreet", "Last":"Kaur"}) dictionaries.append({"First":"Mohamad", "Last":"Argani"}) for i in range(0, len(dictionaries)):     # Condition that's print the full name when Condition is True   if(dictionaries[i]['First']=='Bob')or(dictionaries[i]['Last']=='Kaur'):     print(dictionaries[i]['First']+" "+dictionaries[i]['Last']) ********************************** please modify the code to use a while loop instead of a for loop
numUniqueValues ♡ Language/Type: Related Links: Java Set collections List Write a method named numUnique Values that accepts a List of integers as a parameter and returns the number of unique integer values in the list. For example, if a list named 1 contains the values [3, 7, 3, -1, 2, 3, 7, 2, 15, 15], the call of numUniqueValues (1) should return 5. If passed the empty list, you should return 0. Use a Set as auxiliary storage to help you solve this problem. Do not modify the list passed in. 6 7 8 9 10 Method: Write a Java method as described, not a complete program or class. 12345
Remove Char This function will be given a list of strings and a character. You must remove all occurrences of the character from each string in the list. The function should return the list of strings with the character removed. Signature: public static ArrayList<String> removeChar(String pattern, ArrayList<String> list) Example:list: ['adndj', 'adjdlaa', 'aa', 'djoe']pattern: a Output: ['dndj', 'djdl', '', 'djoe']
#include <stdio.h>#include <stdlib.h> typedef struct Number_struct { int num;} Number; void Swap(Number* numPtr1, Number* numPtr2) { /* Your code goes here */} int main(void) { Number* num1 = NULL; Number* num2 = NULL; num1 = (Number*)malloc(sizeof(Number)); num2 = (Number*)malloc(sizeof(Number)); int int1; int int2; scanf("%d", &int1); scanf("%d", &int2); Thank you so much but i forgot to put this how i would fit in into this. num1->num = int1; num2->num = int2; Swap(num1, num2); printf("num1 = %d, num2 = %d\n", num1->num, num2->num); return 0;}