Acetic acid in water is to be removed using pure isopropyl ether as solvent. The operation is at 20°C and 1 atm (see figure provided for equilibrium). The feed is 0.45 weight fraction acetic acid and 0.55 weight fraction water. Feed flow rate is 2000 kg/h. A countercurrent system is used. An extract stream that is 0.20 weight fraction acetic acid and a raffinate that is 0.20 weight fraction acetic acid are desired. What is the solvent flow rate required? How many equilibrium stages are required? What are the tie-lines and plait point?
Acetic acid in water is to be removed using pure isopropyl ether as solvent. The operation is at 20°C and 1 atm (see figure provided for equilibrium). The feed is 0.45 weight fraction acetic acid and 0.55 weight fraction water. Feed flow rate is 2000 kg/h. A countercurrent system is used. An extract stream that is 0.20 weight fraction acetic acid and a raffinate that is 0.20 weight fraction acetic acid are desired. What is the solvent flow rate required? How many equilibrium stages are required? What are the tie-lines and plait point?
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Acetic acid in water is to be removed using pure isopropyl ether as solvent. The operation is at 20°C and 1 atm (see figure provided for equilibrium). The feed is 0.45 weight fraction acetic acid and 0.55 weight fraction water. Feed flow rate is 2000 kg/h. A countercurrent system is used. An extract stream that is 0.20 weight fraction acetic acid and a raffinate that is 0.20 weight fraction acetic acid are desired.
- What is the solvent flow rate required?
- How many equilibrium stages are required?
- What are the tie-lines and plait point?
Use the right-angle-triangle diagram provided.
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