Calculate the amount of crystal E coming out as product from the precipitator in kg/min

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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 Calculate the amount of crystal E coming out as product from the precipitator in kg/min

A liquid super conductor E is produced from its water solution by staged evaporation and crystallization (precipitation).
Temperature, "C
Wt% E in
Water Vapor 100°C
saturated solution
20
5.71
30
7.23
100
31.0
Feed Solution 437 kg/min
Saturated solution,
35 kg/min, 20°C
E-0.472%
Water
Evaporator,
20°C
100*C
Pure liquid E.
30°C
Melter,
E dissolved in
water
100°C
Precipitator
and Settler,
30*C
20°C
Solid and some
liquid E (100%
E)
crystal E (pure)
with saturated
solution, 7.06
kg/min, 20°C
30°C
Washer,
Solid and liquid
E (100N E)
30°C
Pure liquid E,
30°C
30°C
saturated
solution, 30°C
Transcribed Image Text:A liquid super conductor E is produced from its water solution by staged evaporation and crystallization (precipitation). Temperature, "C Wt% E in Water Vapor 100°C saturated solution 20 5.71 30 7.23 100 31.0 Feed Solution 437 kg/min Saturated solution, 35 kg/min, 20°C E-0.472% Water Evaporator, 20°C 100*C Pure liquid E. 30°C Melter, E dissolved in water 100°C Precipitator and Settler, 30*C 20°C Solid and some liquid E (100% E) crystal E (pure) with saturated solution, 7.06 kg/min, 20°C 30°C Washer, Solid and liquid E (100N E) 30°C Pure liquid E, 30°C 30°C saturated solution, 30°C
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