A4.1- For a concentrically loaded tied short column, with the cross-section shown in Figure 1, a) Find the axial load resistance of the column; b) Check if the spacing between the longitudinal bars is satisfying code requirements; c) Determine the required spacing between the ties, and sketch the tie arrangement as per the code. Given: f'c = 25 MPa fy = 400 MPa T 550 mm 550 mm Maximum aggregate size: 20mm Longitudinal bars: 8-25M Figure 1 Ties: 10M (ties are not shown on cross-section. The arrangement to be determined in part c) Clear cover to the ties: 40mm , MPa 25 20 20 P₁ = 0.05 0.04 P₁ = 0.03 P = 0.02 15 2/8 10 0 5 P = 0.01 f,/fy = 0.0 fs/fy = 0.5/ Y = 0.60 b f 25 MPa fy = 400 MPa h f/fy = 1.0 1 2 3 5 6 M, MPa Agh

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A4.1- For a concentrically loaded tied short column, with the cross-section shown in Figure 1,
a) Find the axial load resistance of the column;
b) Check if the spacing between the longitudinal bars is satisfying code requirements;
c) Determine the required spacing between the ties, and sketch the tie arrangement
as per the code.
Given: f'c = 25 MPa
fy = 400 MPa
T
550 mm
550 mm
Maximum aggregate size: 20mm
Longitudinal bars: 8-25M
Figure 1
Ties: 10M (ties are not shown on cross-section. The arrangement to be determined in part c)
Clear cover to the ties: 40mm
Transcribed Image Text:A4.1- For a concentrically loaded tied short column, with the cross-section shown in Figure 1, a) Find the axial load resistance of the column; b) Check if the spacing between the longitudinal bars is satisfying code requirements; c) Determine the required spacing between the ties, and sketch the tie arrangement as per the code. Given: f'c = 25 MPa fy = 400 MPa T 550 mm 550 mm Maximum aggregate size: 20mm Longitudinal bars: 8-25M Figure 1 Ties: 10M (ties are not shown on cross-section. The arrangement to be determined in part c) Clear cover to the ties: 40mm
, MPa
25
20
20
P₁ = 0.05
0.04
P₁ = 0.03
P = 0.02
15
2/8
10
0
5
P = 0.01
f,/fy = 0.0
fs/fy = 0.5/
Y = 0.60
b
f
25 MPa
fy
= 400 MPa
h
f/fy = 1.0
1
2
3
5
6
M,
MPa
Agh
Transcribed Image Text:, MPa 25 20 20 P₁ = 0.05 0.04 P₁ = 0.03 P = 0.02 15 2/8 10 0 5 P = 0.01 f,/fy = 0.0 fs/fy = 0.5/ Y = 0.60 b f 25 MPa fy = 400 MPa h f/fy = 1.0 1 2 3 5 6 M, MPa Agh
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