2.6 The following are the results of a sieve and hydrometer analysis. Sieve number/ Analysis grain size Percent finer than Sieve 40 100 80 97 170 92 200 90 Hydrometer 0.04 mm 74 0.015 mm 42 0.008 mm 27 0.004 mm 17 0.002 mm 11 a. Draw the grain-size distribution curve. b. Determine the percentages of gravel, sand, silt, and clay according to the MIT system. c. Repeat Part b according to the USDA system. d. Repeat Part b according to the AASHTO system. WD = ? L=30' ↓ +3 } MD = W 18 x 50 → Sx = ... Мо ор = Sx ≤0.3 Fy ?(900) ? WOLR= 3L2 Mo = [AISCM] 8 (?) (900) 8 8 g = 0.3(50) Sx (?) (8) 2) D+L= MD + ML M₁ = £0.6 Fy = (32)(900) Sx 8 2=(?) (8) MD_ Мс = + Sx Sx 3) Amax LE = 360 WL ↓ ↓ ↓ = 0.6 Fy (30°)(12) 360 SS Beam midspan Amax - Amax 5WL4 => 384EIX K-in => W₁ = k/in k-ft => W₁₂ = K/ft 4 5 WL L 384 E Ix L = 30' E = 29000 ksi I = . (AISCM)
2.6 The following are the results of a sieve and hydrometer analysis. Sieve number/ Analysis grain size Percent finer than Sieve 40 100 80 97 170 92 200 90 Hydrometer 0.04 mm 74 0.015 mm 42 0.008 mm 27 0.004 mm 17 0.002 mm 11 a. Draw the grain-size distribution curve. b. Determine the percentages of gravel, sand, silt, and clay according to the MIT system. c. Repeat Part b according to the USDA system. d. Repeat Part b according to the AASHTO system. WD = ? L=30' ↓ +3 } MD = W 18 x 50 → Sx = ... Мо ор = Sx ≤0.3 Fy ?(900) ? WOLR= 3L2 Mo = [AISCM] 8 (?) (900) 8 8 g = 0.3(50) Sx (?) (8) 2) D+L= MD + ML M₁ = £0.6 Fy = (32)(900) Sx 8 2=(?) (8) MD_ Мс = + Sx Sx 3) Amax LE = 360 WL ↓ ↓ ↓ = 0.6 Fy (30°)(12) 360 SS Beam midspan Amax - Amax 5WL4 => 384EIX K-in => W₁ = k/in k-ft => W₁₂ = K/ft 4 5 WL L 384 E Ix L = 30' E = 29000 ksi I = . (AISCM)
Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN:9781305970939
Author:Braja M. Das, Khaled Sobhan
Publisher:Braja M. Das, Khaled Sobhan
Chapter2: Origin Of Soil And Grain Size
Section: Chapter Questions
Problem 2.5P: Repeat Problem 2.4 with the following data. 2.4 The following are the results of a sieve analysis....
Related questions
Question
The farming plan of steel structure has 30 ft long simply supported beams spaced at 8 ft apart.
The beams carry dead loads (D) and live loads (L). The selected beam size is W 18x50.
1) Based on 0.3Fy allowable stress limit due to dead loads only (D), what will be the
maximum D load in psf that can be applied to the beams? Ignore beam weight.
2) Using the D load obtained from Part 1 and based on 0.6Fy allowable stress limit due to
combined dead loads and live loads, what will be the maximum live load L in psf that
can be applied to the beams?
3) If the maximum mid span deflection due to live loads (L) is L/360 ( or 1.0 in in this case),
what will be the maximum L load in psf that can be applied to the beams?
Transcribed Image Text:2.6
The following are the results of a sieve and hydrometer analysis.
Sieve number/
Analysis
grain size
Percent
finer than
Sieve
40
100
80
97
170
92
200
90
Hydrometer
0.04 mm
74
0.015 mm
42
0.008 mm
27
0.004 mm
17
0.002 mm
11
a. Draw the grain-size distribution curve.
b. Determine the percentages of gravel, sand, silt, and clay according to the
MIT system.
c. Repeat Part b according to the USDA system.
d. Repeat Part b according to the AASHTO system.
![WD = ?
L=30'
↓
+3
}
MD =
W 18 x 50 → Sx = ...
Мо
ор
=
Sx
≤0.3 Fy
?(900)
?
WOLR= 3L2
Mo =
[AISCM]
8
(?) (900)
8
8
g
= 0.3(50)
Sx
(?) (8)
2) D+L=
MD + ML
M₁ =
£0.6 Fy
= (32)(900)
Sx
8
2=(?) (8)
MD_
Мс
=
+
Sx
Sx
3) Amax LE
=
360
WL
↓
↓ ↓
= 0.6 Fy
(30°)(12)
360
SS Beam
midspan
Amax
-
Amax
5WL4
=>
384EIX
K-in => W₁ = k/in
k-ft => W₁₂ =
K/ft
4
5 WL L
384 E Ix
L = 30'
E = 29000 ksi
I = . (AISCM)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbf15b3c9-12b8-4e64-a0bf-6c6d5d98dc14%2Fa81fcc84-2342-4dec-a6e9-2abf35e0f3f9%2F4x7nhrd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:WD = ?
L=30'
↓
+3
}
MD =
W 18 x 50 → Sx = ...
Мо
ор
=
Sx
≤0.3 Fy
?(900)
?
WOLR= 3L2
Mo =
[AISCM]
8
(?) (900)
8
8
g
= 0.3(50)
Sx
(?) (8)
2) D+L=
MD + ML
M₁ =
£0.6 Fy
= (32)(900)
Sx
8
2=(?) (8)
MD_
Мс
=
+
Sx
Sx
3) Amax LE
=
360
WL
↓
↓ ↓
= 0.6 Fy
(30°)(12)
360
SS Beam
midspan
Amax
-
Amax
5WL4
=>
384EIX
K-in => W₁ = k/in
k-ft => W₁₂ =
K/ft
4
5 WL L
384 E Ix
L = 30'
E = 29000 ksi
I = . (AISCM)
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