A well-known brokerage firm executive claimed that 60% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 200 people, 59% of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is smaller than 60% at the .02 significance level. The sample proportion ˆp=p^=  1.)The test statistic is:  (to 2 decimals) 2.)The p-value is:  (to 4 decimals) 3.) Based on this we: a.)Reject the null hypothesis b.)Fail to reject the null hypothesis

Q: A study of 420,054 cell phone users found that 132 of them developed cancer of the brain or nervous…

A:

Q: More carry-on bags for passengers on a flight can delay the loading and un-loading of passengers.…

A: Given:                              Number of favorable cases (X) = 172…

Q: PT. “ABC” in 2018 offers a new portfolio for investment. For this new product, companies need to…

A: Given that :  Older people (x1) = 90 Younger people ( x1) = 70 each of which was taken as many as…

Q: A study of 30 college students showed that 25 are binge watching series. Find a 95% confidence…

A: Given x=25 n=30 95% confidence interval

Q: A study of 420,059 cell phone users found that 135 of them developed cancer of the brain or nervous…

A: Do cell phone users appear to have a rate of cancer of the brain or nervous system that is different…

Q: A random sample of 300 of toy trains produced by a company are selected from a production line and…

A: Given Data: x=60 n=300 p^=xn=60300=0.2   z-value for 95% Confidence level: z=1.96

Q: The culinary herb cilantro, Coriandrum Sativum, is very polarizing: some people love it, and others…

A: 1. A survey of 12,087 American adults asked whether they like or dislike the taste of cilantro in…

Q: According to the website www.collegedrinkingprevention.gov, "About 25 percent of college students…

A: Sample size (n) = 71Sample mean (x̅) = 3.93Standard deviations (s) = 3.78 Confidence level (c) =…

Q: A poll was conducted to determine the popularity of a 3D game creation software that was targeted to…

A: compute sample size ( n ) = n=(Z/E)^2*p*(1-p) Z a/2 at 0.04 level of significance is = 2.054

Q: The herb ginkgo biloba is commonly used as a treatment to prevent dementia. In a study of the…

A: Obtain the right hand critical value at the 99% confidence interval Here, confidence level is 0.99.…

Q: 3) In a sample of 172 JCC full-time students, 61 of them prefer to come to campus to take their…

A: Solution: Given information: n= 172 Sample size of JCC full time students x= 61 students prefer to…

Q: A random sample found that forty percent of 100 Americans were satisfied with the gun control laws…

A: The objective of this question is to compute a 99% confidence interval for the true proportion of…

Q: In a study of accuracy of fast food drive throughs.  McDonalds had 27 orders that were not accurate…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…

Q: Of 400 employees selected randomly from one company, 18.25% of them commute by carpooling. Construct…

A: The sample size n = 400. The probability p is 0.1825 The absolute value of Zα/2 is 1.96 using the…

Q: An investigator conducts a study to investigate whether there is a difference in mean PEF in…

A:

Q: A random sample of 100 patients showed that 60 of those who participate in a drug rehabilitation…

A: a)Suppose p is the true population proportion of all patients who were able to get a job within 3…

Q: dnive-through has a lowe (a) What is the mean service time from the 734 customers? The mean service…

A: given     n=734 lower bound    =154.0 upper bound  =  157.8 the confidence intervals  are   (  x -…

Q: 7 min and a standard deviation of 22.4 min. Assume that the 22 sample values appear to be from a…

A: The random sample of 22 values; n=22 The mean wake time 78.7 and standard deviation 22.4 x=78.7…

Q: A consumer watchdog organization estimates the mean weight of 1-ounce "Fun-Size" candy bars to see…

A:

Q: A sample of 300 of electronic components produced showed 36 non-conforming ones. Construct a 95%…

A: Givensample size(n)=300x=36p^=xn=36300=0.12confidence…

Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…

A: It is given that the sample mean is 77.9 and the standard deviation is 20.4.

Q: A poll conducted asked a random sample of 1342 adults in the United States how much confidence they…

A: Given,             Hypothesis                        It is a Left-tailed test.

Q: The Pew Research Center polled n = 1048 U.S. drivers and found that 69% enjoyed driving their…

A: Given Information: Sample size n=1048 69% enjoyed driving their automobiles.

Q: survey of 2,500 u.s citizens yielded 1,600 who are in favor of gun control legislation. estimate the…

A: According to the given information in this question We need to construct 95% confidence interval

Q: During the filling process of a sunflower oil bottling facility, 8 milk bottles were weighed and the…

A: Given: n=8s2=10 The degrees of freedom is obtained as below: df=n-1=8-1=7 The critical value is…

Q: In a random sample of 1,250 adult drivers, 450 said they would cut their driving by 10 percent is…

A: From the provided information Sample size (n) = 1250 450 said they would cut their driving by 10…

Q: The Harvard school of public health conducted a survey of 2770 adults in the United States to…

A: It is given that sample size n is 2,770 and p hat is 0.26.The point estimate for population…

Q: A physician’s billing office conducted a random check of patient records and found that 36 of 50…

A:

Q: A study of 420,029 cell phone users found that 132 of them developed cancer of the brain or nervous…

A: From the provided information Confidence level = 95% Sample size (n) = 420029 132 of them developed…

Q: wed that 122 involved uninsured drivers. Construct a 96% confidence interval for the proportion of…

A: A survey of 500 non-fatal accidents showed that 122 involved uninsured drivers. Let X be the number…

Q: According to the Government Accountability Office (GAO), women comprise of about 17% of the active…

A: Solution: Let X be the number of women enlisted in the military and n be the sample number of…

Q: A phase three clinical trail for a new medication proposed to treat depression has 1191…

A: Given: Sample size (n) = 1191 Let "x" be the individuals who received the medication experienced…

Q: A soft drink company asked you to conduct a survey on consumer preference on their soft drink…

A: Confidence interval produces a range a values that is supposed to contain the population parameter.

Q: A research center claims that more than 37% of U.S adults eat breakfast everyday. In a random sample…

A: Solution: State the hypotheses Null hypothesis: That is, the proportion of U.S adults eat breakfast…

Q: Results from the National Health and Nutrition Examination Survey (NHANES) conducted thirty years…

A:

Q: Apple Computer believed that 36 percent of its smartphone customer own the most recent model of…

A: Here we conduct Z test for proportion.

Q: Of the 250 students surveyerd, 100 prefered asynchronous distance learning and 150 prefered…

A: sample size (n) = 250p = proportion of student support asynchronous distance learningfavorable…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.