In a survey of 1019 ​adults, a polling agency​ asked, "When you​ retire, do you think you will have enough money to live comfortably or not. Of the 10191 ​surveyed, 536 stated that they were worried about having enough money to live comfortably in retirement. Construct a 90​% confidence interval for the proportion of adults who are worried about having enough money to live comfortably in retirement

Q: In a survey of 3001 ​adults, 1486 say they have started paying bills online in the last year.…

A: Assuming that the number of people paying bills online has a binomial distribution with n=3001, and…

Q: Of 125 adults selected randomly from one town, 28 of them smoke. Construct a 99% confidence interval…

A: It is given that out of 125 adults in one town, 28 of them smoke. That is the value of n is 125 and…

Q: In a survey of 1013 ​adults, a polling agency​ asked, "When you​ retire, do you think you will have…

A: From the provided information, Sample size (n) = 1013 Out of which 531 stated that they were worried…

Q: A survey of 120 female freshmen showed that 9 did not wish to work after marriage.  Find the 99%…

A:

Q: n a survey of 2558 ​adults, 1413 say they have started paying bills online in the last year.…

A: Solution: Given information: n= 2558 Sample size of adults  x = 1413 adults started paying bills…

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: In a survey of 3254 ​adults, 1433 say they have started paying bills online in the last year.…

A: Given X=1433 n=3254

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In poll,…

A:

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: An accounting firm has 1200 clients. From a random sample of 120 clients, 110 indicated very high…

A: Given : An accounting firm has 1200 clients So,  Population size (N) = 1200 Sample size (n) = 120…

Q: A survey​ asked, "How many tattoos do you currently have on your​ body?" Of the 1227 males​…

A:

Q: In a survey of 1400 people, 75% indicated that they listened to their favorite radio station because…

A: In statistical inference there are two branches-1)hypothesis testing and 2)Estimation In estimation…

Q: A sample of 500 nursing applicants included 80 men.  Determine the 95% confidence interval for the…

A:

Q: In a survey of 1037 US adults ages 65 and over, 643 were concerned about getting the flu. A 99%…

A: Given,n=1037x=643p^=xnp^=6431037=0.6201-p^=1-0.620=0.380α=1-0.99=0.01α2=0.005Z0.005=2.58    (from…

Q: In a survey of 50,00 people, 80% indicated that they listened to their favorite radio station…

A: Hern= 5000 P^ = 0.80 We have to construct 95% ci for p

Q: In a survey of 2552 ​adults, 1423 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2552 adults, 1423 say they have started paying bills online in the last…

Q: A pollster wanted to predict the upcoming results of the 2020 presidential elections in a local…

A:

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: when 282 college students are randomly selected and surveyed, it is found that 109 own a car. find a…

A: It is given that sample size (n) is 282 and x is 109.

Q: Out of 300 people sampled, 171 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A: Given , n = 1008 x = 598

Q: 2. Construct a 95% confidence interval to estimate the proportion of Wingate female students that…

A: total number of female students =181 number of students who are left handed=15

Q: A survey of 800 women shoppers found that 15% of them shop on impulse.  What is the 95% confidence…

A: n = 800p^ = 0.1595% CI for p = ?

Q: A survey of 300 women shoppers found that 17% of them shop on impulse. What is the 80% confidence…

A: From the provided information,A survey of 300 women shoppers found that 17% of them shop on impulse.…

Q: In a sample of 300 people, 48 identified as dog owners. Construct a 99% confidence interval for the…

A: Obtain the 99% confidence interval for the true proportion of people who are dog owners. The 99%…

Q: In a survey of 2782 adults, 1411 say they have started paying bills online in the last year.…

A:

Q: In a survey of 1008 adults, a polling agency asked, "When you retire, do you think you will have…

A:

Q: Out of 300 people sampled, 279 had kids. Based on this, construct a 90% confidence interval for the…

A:

Q: In a survey of 1,626,773 U.S. adults, 49,311 personally identified as lesbian, gay, bisexual, or…

A:

Q: In a survey of 3071 ​adults, 1484 say they have started paying bills online in the last year.…

A: Given, Therefore, As per z-distribution table the critical value of z at 0.01 level of significant…

Q: An internet service provider sampled 540 customers and found that 55 of them experienced an…

A:

Q: In a survey of 3342 adults, 1489 say they have started paying bills online in the last year.…

A: Given Information: To construct a 99% confidence interval for the population proportion and…

Q: In a survey of 3426 ​adults, 1487 say they have started paying bills online in the last year.…

A: From the provided information, Sample size (n) = 3426 Out of which 1487 say they have started paying…

Q: A random survey of 36 airline passengers indicates that twelve have never flown before. Find a 95%…

A: We have given that,  Sample size (n) = 36 and favorable cases         (X) = 12 Then,  We Will find…

Q: A marketing study by Ford Motor Company finds that 320 of the 650 buyers of compact cars were women.…

A: Let the population proportion of women who bought compact cars be P Given:         Sample size n =…

Q: An actuary is interested in estimating the proportion of young adults who plan to have children…

A: We need to construct the 99% confidence interval for the population proportion. We have been…

Q: In a random sample of 250 high school students, it was found that 85.2% (213) of them later…

A:

Q: Out of 100 people sampled, 54 had kids. Based on this, construct a 90 % confidence interval for the…

A:

Q: n 2013, the Gallup poll asked 1,039 American adults if they believe there was a conspiracy in the…

A: Given data, n=1039 x=634 sample proportion p=x/n =634/1039 =0.61   z-value at 90% confidence is…

Q: Out of a survey of 900 adults, 567 said that teenagers were more dangerous drivers than senior…

A: Givensample size(n)=900No.of adults said that teenagers were more dangerous divers(x)=567sample…

Q: Of 130 adults selected randomly from one town, 30 of them smoke. Construct a 90% confidence interval…

A:

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.