In a survey of 1013 ​adults, a polling agency​ asked, "When you​ retire, do you think you will have enough money to live comfortably or not. Of the 1013 ​surveyed, 531 stated that they were worried about having enough money to live comfortably in retirement. Construct a 90​% confidence interval for the proportion of adults who are worried about having enough money to live comfortably in retirement.

Q: rifle at the target on the (x, y) plane. A boy shoots at the target on the (x, y actual point in…

A:

Q: In a survey of 3001 ​adults, 1486 say they have started paying bills online in the last year.…

A: Assuming that the number of people paying bills online has a binomial distribution with n=3001, and…

Q: In a survey of 2865 ​adults, 1413 say they have started paying bills online in the last year.…

A:

Q: In a Gallup poll of 804 randomly selected adults living in the 50 U.S. states and the District of…

A: Answer x =466n =804Confidence interval =95%

Q: In a survey of 4026 ​adults, 708 oppose allowing transgender students to use the bathrooms of the…

A: Given:  n=4026 x=708

Q: A survey of 120 female freshmen showed that 9 did not wish to work after marriage.  Find the 99%…

A:

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: In a survey of 3254 ​adults, 1433 say they have started paying bills online in the last year.…

A: Given X=1433 n=3254

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In poll,…

A:

Q: In a survey of 3478 adults, 1462 say they have started paying bills online in the last year.…

A: From the provided information,Confidence level = 99%

Q: In a survey of 2703 ​adults, 1438 say they have started paying bills online in the last year.…

A: We have given that, Number of favorable cases(X) = 1438,   Sample size(n) = 2703 Sample proportion…

Q: In a survey of 1,200 social media users, 56% said it is not okay to be friends with your boss.…

A:

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: In a survey of 3985 ​adults, 711 oppose allowing transgender students to use the bathrooms of the…

A: Given, n=3985 x=711 To find a confidence interval for a population proportion.

Q: A survey​ asked, "How many tattoos do you currently have on your​ body?" Of the 1227 males​…

A:

Q: In a survey of 4008 ​adults, 728 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In a survey of 4052 ​adults, 723 oppose allowing transgender students to use the bathrooms of the…

A: It is given that x = 723 and n= 4,052.

Q: In a survey of 1400 people, 75% indicated that they listened to their favorite radio station because…

A: In statistical inference there are two branches-1)hypothesis testing and 2)Estimation In estimation…

Q: et X be the amount of time (in hours) the wait is to get a table at a restaurant. Suppose the cdf is…

A: Given that  Cdf. F(x)= {0   x<0           {X3/64  , 0<=x<=4              0     , x>4

Q: In a survey of 1037 US adults ages 65 and over, 643 were concerned about getting the flu. A 99%…

A: Given,n=1037x=643p^=xnp^=6431037=0.6201-p^=1-0.620=0.380α=1-0.99=0.01α2=0.005Z0.005=2.58    (from…

Q: In a survey of 2552 ​adults, 1423 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2552 adults, 1423 say they have started paying bills online in the last…

Q: In a survey of 3260​ adults, 1456 say they have started paying bills online in the last year.…

A: Givenn=3260x=1456p^=xn=14563260=0.4466

Q: A pollster wanted to predict the upcoming results of the 2020 presidential elections in a local…

A:

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A: Given , n = 1008 x = 598

Q: A survey of 800 women shoppers found that 15% of them shop on impulse.  What is the 95% confidence…

A: n = 800p^ = 0.1595% CI for p = ?

Q: Construct a​ 99% confidence interval for the population proportion. Interpret the results.

A:

Q: n a survey of 3932 ​adults, 718 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In a survey of 3983 ​adults, 747 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In a survey of 2782 adults, 1411 say they have started paying bills online in the last year.…

A:

Q: In a survey of 2745 ​adults, 1477 say they have started paying bills online in the last year.…

A: Given, n= 2745 x=1477 The sample proportion is given by: p^=xn=14772745=0.5381 Also, α=0.99…

Q: In a survey of 1008 adults, a polling agency asked, "When you retire, do you think you will have…

A:

Q: In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last…

Q: Out of 300 people sampled, 279 had kids. Based on this, construct a 90% confidence interval for the…

A:

Q: In a survey of 3071 ​adults, 1484 say they have started paying bills online in the last year.…

A: Given, Therefore, As per z-distribution table the critical value of z at 0.01 level of significant…

Q: n a survey of 2847 ​adults, 1408 say they have started paying bills online in the last year.…

A: Given that  Sample size (n) =2847 People started paying bills online (x) = 1408 Proportion (p) =…

Q: In a survey of 3426 ​adults, 1487 say they have started paying bills online in the last year.…

A: From the provided information, Sample size (n) = 3426 Out of which 1487 say they have started paying…

Q: n a survey of 3196 adults, 1405 say they have started paying bills online in the last year.…

A: Given data, n=3196 x=1405 p=x/n=1405/3196 =0.4396 z-value at 99% confidence is Zc=2.576

Q: In a survey of 2588 ​adults, 1466 say they have started paying bills online in the last year.…

A: Construct 99% confidence interval for population proportion:The sample of 2,588 adults among that…

Q: An actuary is interested in estimating the proportion of young adults who plan to have children…

A: We need to construct the 99% confidence interval for the population proportion. We have been…

Q: In a survey of 3246 ​adults, 1418 say they have started paying bills online in the last year.…

A: Given information Number of adults surveyed(n) = 3246 Number of people who started paying bills…

Q: In a random sample of 250 high school students, it was found that 85.2% (213) of them later…

A:

Q: Out of 100 people sampled, 54 had kids. Based on this, construct a 90 % confidence interval for the…

A:

Q: n 2013, the Gallup poll asked 1,039 American adults if they believe there was a conspiracy in the…

A: Given data, n=1039 x=634 sample proportion p=x/n =634/1039 =0.61   z-value at 90% confidence is…

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.