The Pew Research Center polled n = 1048 U.S. drivers and found that 69% enjoyed driving their automobiles.14 (a) Construct a 95% confidence interval for the proportion of U.S. drivers who enjoy driving their automobiles. (b) In 1991, a Gallup Poll reported this percent to be 79%. Using the data from this poll, test the claim that the percent of drivers who enjoy driving their cars has declined since 1991. Report the large-sample z statistic and its P-value.

Q: According to a poll, 81% of California adults (409 out of 506 surveyed) feel that education is one…

A: Point estimate=0.81

Q: If a 92% Confidence Interval for the Population Mean is (67.8, 78.9), find its Margin of Error.

A:

Q: Several years ago, 50% of parents who had children in grades K-12 were satisfied with the quality of…

A: Given claim: 50% of the parents who had children in grades K-12 were satisfied with the quality of…

Q: Suppose a different police department says their SRS resulted in a 95% confidence interval of 10.1%…

A:

Q: 2. A 90% confidence interval for the mean percentage of airline reservations being canceled on the…

A: 2. The point estimator for µ is calculated by using the formula:

Q: We wish to estimate what per cent of 18 to 25-year old's that own a Samsung phone. Out of 400…

A:

Q: Data from the National Health Interview Survey (NHIS): Group Sample Size Health Status Std. Error…

A: There are 2 categories of the people who have visited hospital recently and other doesn't visited…

Q: A car repair business randomly selects receipts for parts purchased on 16 different jobs. The mean…

A: given data, n=16x¯=31.32s=30.42CI=0.95α=1-0.95=0.05df=n-1=16-1=15we  have to construct the 95%…

Q: Several years ago, 53% of parents who had children in grades K-12 were satisfied with the quality of…

A: In statistical inference, there are two types of estimation,  Point estimation and Interval…

Q: An issue of Time Style and Design reported on a poll conducted by Schulman Ronca & Bucuvalas Public…

A: (a)given that,possible chances (x)=410size(n)=603success rate ( p )= x/n = 0.6799point of estimate =…

Q: The internal auditing staff of a local manufacturing company performs a sample audit each quarter to…

A:

Q: Several years ago, 33% of parents who had children in grades K-12 were satisfied with the quality of…

A: The formula for the confidence interval for the proportion is, Here, confidence level is 0.90. Use…

Q: Define the confidence level?

A: It is the likelihood of containing the true population parameter under the confidence interval when…

Q: Find a 95% confidence interval for the proportion of all U.S. adults with household incomes of at…

A: We need to construct the 95%95\%confidence interval for the population proportion. We have been…

Q: According to the American Medical Association, the average annual of radiologists in the USA are…

A:

Q: It is required to construct a (1−?)100% confidence interval for the true population median, M using…

A: A sign test is non-parametric. In case of a sign test, we compare the medians, M, instead of the…

Q: 99% confidence interval for the proportion of the high school students who have been cyberbullied,…

A: Given that Sample size n = 14795 Number of high school students who have cyberbullied, X = 2219 The…

Q: Find the critical t value to use in making a 98% confidence interval for a mean if the sample size…

A:

Q: packer produces 1,200 packages of ham per shift, how many packages should the Quality Control area…

A: To find the confidence level of 95%.

Q: An issue of Time Style and Design reported on a poll conducted by Schulman Ronca & Bucuvalas Public…

A: (a)given that,possible chances (x)=410size(n)=603success rate ( p )= x/n = 0.6799point of estimate =…

Q: A recent study asked U.S. adults to name 10 historic events that occurred in their lifetime that…

A: We have given that,  Sample proportion (p̂) = 76% = 0.76 and sample size (n) = 2025 Then,  We will…

Q: A student read that a 95% confidence interval for the mean age an American first drinks alcohol is…

A: Lower limit = 16 - 1.2 =14.8 Lower limit = 16 + 1.2 =17.2

Q: What does Level of Confidence indicates?

A:

Q: According to a poll, 77% of California adults (389 out of 506 surveyed) feel that education is one…

A: Given that the number of favorable cases Favorable Cases XX = 389389 Sample Size NN = 506506…

Q: In a survey of 1007 parents of children ages 8 to 14, 75% say they are willing to get a second job…

A: Given information- A proportion of parents say they are willing to get a second job or part-time…

Q: A sample of 1,000 employees in an international company was taken to estimate the average…

A: Confidence interval of mean is given by, (X bar + - Z* sigma/√n) Where X bar is mean and sigma is…

Q: What are two ways to get a narrower confidence interval for a proportion?

A: Two ways to get a narrower confidence interval for a proportion are:

Q: In a survey 800 randomly selected 16 to 18 years old living in USA were asked whether they have ever…

A:

Q: I need help with creating a confidence interval using gender as a healthcare variable

A: Here, we can can use the sample proportions relating to a particular gender type to find the effect…

Q: iew 8.2 of your te ect Help tab below fidence interval ca watch Excel videa ew 8.3 of your text ect…

A: In above scenario we have to deal with confidence interval for population proportion. The formula…

Q: Several years ago, 33% of parents who had children in grades K-12 were satisfied with the quality of…

A: According to the given information in this question, we need to identify null and alternative…

Q: 700 randomly selected Americans were asked if they believed the minimum wage should be raised. 350…

A: Given that  p = 700 x = 350 Confidence level(c) = 90% = 0.90 Significance level (α) = 1-c = 1-0.90=…

Q: We wish to estimate what percent of 18 to 25-year old's that own a Samsung phone. Out of 400…

A: Solution: Let X be the number of adults own a Samsung phone and n be the sample number of adults.…

Q: several years ago, 48% of parents who had children in grades K-12 were satisfied with the quality of…

A: Given that  Sample size n =1035 Favorable cases x =497 Sample proportion p^=x/n  =497/1035 =0.4802

Q: 10)The superintendent of a golf course believes that the mean score for professional golfers on his…

A: We have to find confidence interval for population mean. Since population standard deviation () now…

Q: An insurance company collects data on​ seat-belt use among drivers in a country. Of 1200drivers…

A:

Q: In a survey of 891 U.S. adults who follow baseball in a recent year, 184 said that the Boston Red…

A: We have given that,  Sample size (n) = 891 and favorable cases (x) = 184 Then,  90% confidence…