A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random sample by the National Institutes of Health included 2253 men and2629 women in this age group. The survey found that 986 of the men and 923 of the women lived with their parents. Construct and interpret a 99% confidenceinterval for the difference in the true proportions of men and women aged 19 to 25 who live in their parents' homes.What conditions are met? (select all that apply) (Remember you check BOTH populations.)O 923 > 30O 10(923) < all women aged 19 to 25O 986 > 30O 2253 > 30O a random sampleV 2629 > 30O 986 > 10O 10(2629) < all women aged 19 to 25a random sampleO 1267 > 10O 1706 > 10O 923 > 10O 10(986) < all men aged 19 to 25O 10(2253) < all men aged 19 to 25O O

Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Answered: A surprising number of young adults…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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