A water solution contains 60% Na2S202 together with 1% soluble impurity. Upon cooling to 10°C, Na2S202 5 H20 crystallizes out. The solubility of this hydrate is 1.4lb Na2S202 5 H20/lb free water. The crystals removed carry asadhering solution 0.06 lb solution/lb crystals. When dried to remove the remaining water (but not the water of hydration), the final dry Na2S202 5 H20 crystals must not contain more than 0.1% impurity. To meet this specification, the original solution, before cooling, is further diluted with water. On the basis of 100 Ib of the original solution,calculate (a) the amount of water added before cooling, and (b) the percentage recoveryof the Na2S202 in the dried hydrated crystals
A water solution contains 60% Na2S202 together with 1% soluble impurity. Upon cooling to 10°C, Na2S202 5 H20 crystallizes out. The solubility of this hydrate is 1.4lb Na2S202 5 H20/lb free water. The crystals removed carry asadhering solution 0.06 lb solution/lb crystals. When dried to remove the remaining water (but not the water of hydration), the final dry Na2S202 5 H20 crystals must not contain more than 0.1% impurity. To meet this specification, the original solution, before cooling, is further diluted with water. On the basis of 100 Ib of the original solution,calculate (a) the amount of water added before cooling, and (b) the percentage recoveryof the Na2S202 in the dried hydrated crystals
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
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Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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![A water solution contains 60% Na2S202
together with 1% soluble impurity. Upon cooling to
10°C, Na2S202
• 5 H2O crystallizes out. The solubility of this hydrate is 1.4lb
Na2S202
• 5 H20/lb free water. The crystals removed carry asadhering
solution 0.06 lb
solution/lb crystals. When dried to remove the remaining
water (but not the water of hydration), the final dry Na2S202
5 H20 crystals must not contain more than 0.1%
impurity. To meet this specification, the original
solution, before cooling, is further diluted
with water. On the basis of 100 Ib of the original
solution,calculate (a) the amount of
water added before cooling, and (b) the percentage
recoveryof the Na2S202
in the dried hydrated crystals](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fba8da9d3-c6a9-4aa9-a43f-637c4c91b019%2Fff90fc78-9b9d-4fe7-bcc2-407d3bfebb65%2Fj9hvkue_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A water solution contains 60% Na2S202
together with 1% soluble impurity. Upon cooling to
10°C, Na2S202
• 5 H2O crystallizes out. The solubility of this hydrate is 1.4lb
Na2S202
• 5 H20/lb free water. The crystals removed carry asadhering
solution 0.06 lb
solution/lb crystals. When dried to remove the remaining
water (but not the water of hydration), the final dry Na2S202
5 H20 crystals must not contain more than 0.1%
impurity. To meet this specification, the original
solution, before cooling, is further diluted
with water. On the basis of 100 Ib of the original
solution,calculate (a) the amount of
water added before cooling, and (b) the percentage
recoveryof the Na2S202
in the dried hydrated crystals
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