A student determines the value of the equilibrium constant to be 1.98×10-5 for the following reaction. CO2(g) + H2(g)CO(g) + H2O(g) Based on this value of Keq: G° for this reaction is expected to be (greater, less) fill in the blank 1 than zero. Calculate the free energy change for the reaction of 1.74 moles of CO2(g) at standard conditions at 298K. G°rxn = kJ

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Q: AH£/kkalmol-1 ASP /kalmol-1 K-1..... 49,15 -4,8 -71,0 -68,3 ..... .... 59,4 7,62 16,72 ..... ...

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