A stream that is 40 mole % benzene and the balance toluene is fed to a separator where it is split into two output streams: top and bottom. The molar flow rate of the feed is 4552 kmol/hr. The isothermal process occurs at 100 °C and the temperature is a constant 10 bar. Determine the total molar flow rate and the flow rates of benzene and toluene (kmol/h) of the top output stream if: (a) 25% of benzene and toluene fed leave in the top. (b) 62% of benzene and toluene fed leave in the top.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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### Stream Separation Problem in Chemical Process Engineering

#### Problem Statement:
A stream that is 40 mole % benzene and the balance toluene is fed to a separator where it is split into two output streams: top and bottom. The molar flow rate of the feed is 4552 kmol/hr. The isothermal process occurs at 100 °C and the pressure is constant at 10 bar.

#### Task:
Determine the total molar flow rate and the flow rates of benzene and toluene (kmol/hr) of the top output stream if:
- (a) 25% of benzene and toluene fed leave in the top.
- (b) 62% of benzene and toluene fed leave in the top.

#### Details:

1. **Feed Stream Composition and Flow:**
   - Benzene: 40 mole %
   - Toluene: 60 mole %
   - Total Feed Flow Rate: 4552 kmol/hr

2. **Operating Conditions:**
   - Temperature: 100 °C
   - Pressure: 10 bar

3. **Output Cases:**
   - **Case (a):** 25% of benzene and toluene fed leave in the top.
   - **Case (b):** 62% of benzene and toluene fed leave in the top.

The goal is to calculate the molar flow rates of benzene and toluene in the top stream for both cases (a) and (b).

---

### Solution Approach:

#### For Case (a):
1. **Total Molar Flow Rate to Top Stream:**
   \( \text{Flow rate to top stream} = 0.25 \times \text{Total feed flow rate} \)
   \( = 0.25 \times 4552 \, (\text{kmol/hr}) \)
   \( = 1138 \, (\text{kmol/hr}) \)

2. **Flow Rate of Benzene in Top Stream:**
   \( \text{Benzene in top stream} = 0.25 \times (\text{40% of 4552 kmol/hr}) \)
   \( = 0.25 \times 1820.8 \, (\text{kmol/hr}) \)
   \( = 455.2 \, (\text{kmol/hr}) \)

3. **Flow Rate of
Transcribed Image Text:### Stream Separation Problem in Chemical Process Engineering #### Problem Statement: A stream that is 40 mole % benzene and the balance toluene is fed to a separator where it is split into two output streams: top and bottom. The molar flow rate of the feed is 4552 kmol/hr. The isothermal process occurs at 100 °C and the pressure is constant at 10 bar. #### Task: Determine the total molar flow rate and the flow rates of benzene and toluene (kmol/hr) of the top output stream if: - (a) 25% of benzene and toluene fed leave in the top. - (b) 62% of benzene and toluene fed leave in the top. #### Details: 1. **Feed Stream Composition and Flow:** - Benzene: 40 mole % - Toluene: 60 mole % - Total Feed Flow Rate: 4552 kmol/hr 2. **Operating Conditions:** - Temperature: 100 °C - Pressure: 10 bar 3. **Output Cases:** - **Case (a):** 25% of benzene and toluene fed leave in the top. - **Case (b):** 62% of benzene and toluene fed leave in the top. The goal is to calculate the molar flow rates of benzene and toluene in the top stream for both cases (a) and (b). --- ### Solution Approach: #### For Case (a): 1. **Total Molar Flow Rate to Top Stream:** \( \text{Flow rate to top stream} = 0.25 \times \text{Total feed flow rate} \) \( = 0.25 \times 4552 \, (\text{kmol/hr}) \) \( = 1138 \, (\text{kmol/hr}) \) 2. **Flow Rate of Benzene in Top Stream:** \( \text{Benzene in top stream} = 0.25 \times (\text{40% of 4552 kmol/hr}) \) \( = 0.25 \times 1820.8 \, (\text{kmol/hr}) \) \( = 455.2 \, (\text{kmol/hr}) \) 3. **Flow Rate of
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