100.0 mol/s of a liquid mixture of pentane and hexane is fed into an evaporator. In the evaporator, the pressure is reduced to 1.5 atm and part of the feed vaporizes. The temperature and pressure of the feed are: 80°C and 5.00 atm, respectively. The temperature in the tank is maintained at 65°C by adding heat. The vapor and liquid phases that are formed in the process exit the evaporation as separate streams. The liquid product stream contains 41.0 mole% pentane. The vapor stream contains 65.6% mol % pentane. The flowchart of the process is given below. a. Determine the flow rate of pentane in the liquid product stream as mol/s b. Determine the flow rate of pentane in the vapor product stream as mol/s c. Determine the flow rate of hexane in the liquid product stream as mol/s

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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100.0 mol/s of a liquid mixture of pentane and hexane is fed into an evaporator. In the evaporator, the pressure is reduced to 1.5 atm and part of the feed vaporizes. The temperature and pressure of the feed are: 80°C and 5.00 atm, respectively. The temperature in the tank is maintained at 65°C by adding heat. The vapor and liquid phases that are formed in the process exit the evaporation as separate streams. The liquid product stream contains 41.0 mole% pentane. The vapor stream contains 65.6% mol % pentane. The flowchart of the process is given below.

a. Determine the flow rate of pentane in the liquid product stream as mol/s

b. Determine the flow rate of pentane in the vapor product stream as mol/s

c. Determine the flow rate of hexane in the liquid product stream as mol/s

Vapor product
1= liquid
65°C, 1.5 atm
v=vapor
P = pentane
Ypl 0.656 mol P(v)/mol
H = hexane
%3D
100 mol/s, liquid
EVAPORATOR
50 mole% P
50 mole% H
Ö(kW)
80°C, 5.0 atm
Liquid product
65°C, 1.5 atm
Xp = 0.41 mol P(1)/mol
%3D
Transcribed Image Text:Vapor product 1= liquid 65°C, 1.5 atm v=vapor P = pentane Ypl 0.656 mol P(v)/mol H = hexane %3D 100 mol/s, liquid EVAPORATOR 50 mole% P 50 mole% H Ö(kW) 80°C, 5.0 atm Liquid product 65°C, 1.5 atm Xp = 0.41 mol P(1)/mol %3D
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