For the flow diagram below, use two material balances and three constraints to determine all unknowns except for the outlet temperature T3. A g H20(1)/s n2 (mol H2O(1)/s) B °C C L air/s n, (mol/s) Пз (molls) х, (mol H,0 (v) /mol) (1-x,) (mol DA/mol) D °C, E torr Tdo = F °C X3 (mol H,O(v)/mol) (1-x3) (mol DA/mol) T3 (°C), 1 atm
For the flow diagram below, use two material balances and three constraints to determine all unknowns except for the outlet temperature T3. A g H20(1)/s n2 (mol H2O(1)/s) B °C C L air/s n, (mol/s) Пз (molls) х, (mol H,0 (v) /mol) (1-x,) (mol DA/mol) D °C, E torr Tdo = F °C X3 (mol H,O(v)/mol) (1-x3) (mol DA/mol) T3 (°C), 1 atm
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
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A stream of air at 500.0 °C and 835 torr with a dew point of 10.0 °C flowing at a rate of 1515 L/s is to be cooled in a spray cooler.
A fine mist of liquid water at 15.0 °C is sprayed into the hot air at a rate of 120.0 g/s and evaporates completely.
The cooled air emerges at 1 atm.
![For the flow diagram below, use two material balances and three constraints to determine all unknowns except for the outlet
temperature T3.
A g H20(1)/s
n2 (mol H,O(1)/s)
B °C
C L air/s
n, (mol/s)
n3 (mol/s)
X, (mol H,О (v) Imol)
(1-x,) (mol DA/mol)
D °C, E torr
Tdo =
X3 (mol H20(v)/mol)
(1-x3) (mol DA/mol)
T3 (C), 1 atm
F °C
Assume A = 120.0 g, B = 15.0 °C, C = 1515 L, D = 500.0°C, E = 835 torr, F = 10.0°C.
n =
i
! mol/s
i
! mol/s
n3
i
! mol/s
X1=
i
mol H20(v)/mol
X3 =
mol H20(v)/mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F73303aca-d795-4569-9e8f-a8984c4a41f6%2Fbbdf8696-9a67-4172-9fb6-1358778f8fd3%2Fl18agse_processed.png&w=3840&q=75)
Transcribed Image Text:For the flow diagram below, use two material balances and three constraints to determine all unknowns except for the outlet
temperature T3.
A g H20(1)/s
n2 (mol H,O(1)/s)
B °C
C L air/s
n, (mol/s)
n3 (mol/s)
X, (mol H,О (v) Imol)
(1-x,) (mol DA/mol)
D °C, E torr
Tdo =
X3 (mol H20(v)/mol)
(1-x3) (mol DA/mol)
T3 (C), 1 atm
F °C
Assume A = 120.0 g, B = 15.0 °C, C = 1515 L, D = 500.0°C, E = 835 torr, F = 10.0°C.
n =
i
! mol/s
i
! mol/s
n3
i
! mol/s
X1=
i
mol H20(v)/mol
X3 =
mol H20(v)/mol
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