A solution that may contain Cu2+ , Bi2+ , Sn4+ , or Sb2+ is treated with thioacetamide in an acidic medium. The black precipitate which forms is partly soluble in strongly basic solution. The precipitate which remains is soluble in 6 M HNO3 and gives only a white precipitate upon the addition of NH4OH. The basic solution, when acidified, produces an orange precipitate. Which group II ions are present? Which are absent? Which are in doubt? How would you remove all doubt?
A solution that may contain Cu2+ , Bi2+ , Sn4+ , or Sb2+ is treated with thioacetamide in an acidic medium. The black precipitate which forms is partly soluble in strongly basic solution. The precipitate which remains is soluble in 6 M HNO3 and gives only a white precipitate upon the addition of NH4OH. The basic solution, when acidified, produces an orange precipitate. Which group II ions are present? Which are absent? Which are in doubt? How would you remove all doubt?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A solution that may contain Cu2+ , Bi2+ , Sn4+ , or Sb2+ is treated with thioacetamide in an acidic medium. The black precipitate which forms is partly soluble in strongly basic solution. The precipitate which remains is soluble in 6 M HNO3 and gives only a white precipitate upon the addition of NH4OH. The basic solution, when acidified, produces an orange precipitate. Which group II ions are present? Which are absent? Which are in doubt? How would you remove all doubt?
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