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11. A solution is prepared by dissolving 25.0 g of ammonium sulfate in 100 mL of solution. Then, 10.0 mL of this stock was added to 50.0 mL of water. Calculate the concentrations of ammonium and sulfate in the final solution. Assume the volumes are additive. Imol Oo189 13a.149 moles Concentration of original ammonium sulfate solution: 1.89 M NHY2 Concentration of final solution (total volume = 60 mL) after dilution: MIV1 = M2V2 M2 = 0.315 M (NH4)2SO4 M (SO,2-) = 0.315 M SO M (NH4) = 2 x (0.315) = 0.630 M NH4

11. A solution is prepared by dissolving 25.0 g of ammonium sulfate in 100 mL of solution. Then, 10.0 mL of this stock was added to 50.0 mL of water. Calculate the concentrations of ammonium and sulfate in the final solution. Assume the volumes are additive. Imol Oo189 13a.149 moles Concentration of original ammonium sulfate solution: 1.89 M NHY2 Concentration of final solution (total volume = 60 mL) after dilution: MIV1 = M2V2 M2 = 0.315 M (NH4)2SO4 M (SO,2-) = 0.315 M SO M (NH4) = 2 x (0.315) = 0.630 M NH4

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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11. A solution is prepared by dissolving 25.0g of ammonium sulfate in 100 mL of solution. Then, 10.0 mL of this stock was added to 50.0 mL of water. Calculate the concentrations of ammonium and sulfate in the final solution. Assume the volumes are additive. 25g Imol 0.189 132.149 moles Concentration of original ammonium sulfate solution: 1.89 M NHY2 Concentration of final solution (total volume = 60 mL) after dilution: M¡V1 = M2V2 M2 = 0.315 M (NH4)2SO4 M (SO4²-) = 0.315 M SO, M (NH4*) = 2 x (0.315) = 0.630 M NH4*
Transcribed Image Text:11. A solution is prepared by dissolving 25.0g of ammonium sulfate in 100 mL of solution. Then, 10.0 mL of this stock was added to 50.0 mL of water. Calculate the concentrations of ammonium and sulfate in the final solution. Assume the volumes are additive. 25g Imol 0.189 132.149 moles Concentration of original ammonium sulfate solution: 1.89 M NHY2 Concentration of final solution (total volume = 60 mL) after dilution: M¡V1 = M2V2 M2 = 0.315 M (NH4)2SO4 M (SO4²-) = 0.315 M SO, M (NH4*) = 2 x (0.315) = 0.630 M NH4*
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