What is the approximate concentration of free Cu²+ ion at equilibrium when 1.05x10-2 mol copper(II) nitrate is added to 1.00 L of solution that is 1.270 M in NH3. For [Cu(NH3)4]²+, Kf = 2.1×10¹³. [Cu²+] = M

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What is the approximate concentration of free Cu²+ ion at equilibrium
when 1.05x10-² mol copper(II) nitrate is added to 1.00 L of
solution that is 1.270 M in NH3. For [Cu(NH3)4]²+, Kƒ = 2.1×10¹³.
[Cu²+] =
M
Transcribed Image Text:What is the approximate concentration of free Cu²+ ion at equilibrium when 1.05x10-² mol copper(II) nitrate is added to 1.00 L of solution that is 1.270 M in NH3. For [Cu(NH3)4]²+, Kƒ = 2.1×10¹³. [Cu²+] = M
In the presence of excess OH, the Zn²+(aq) ion forms a hydroxide complex ion,
2-
Zn(OH)4²-. Calculate the concentration of free Zn²+ ion when 1.23×10-² mol ZnSO4(s)
is added to 1.00 L of solution in which [OH-] is held constant (buffered at pH 12.10). For
2-
Zn(OH)4²¯, Kf = 4.6×10¹7.
[Zn²+] =
M
Transcribed Image Text:In the presence of excess OH, the Zn²+(aq) ion forms a hydroxide complex ion, 2- Zn(OH)4²-. Calculate the concentration of free Zn²+ ion when 1.23×10-² mol ZnSO4(s) is added to 1.00 L of solution in which [OH-] is held constant (buffered at pH 12.10). For 2- Zn(OH)4²¯, Kf = 4.6×10¹7. [Zn²+] = M
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