A sample of a substance with the empirical formula XCl₂ weighs 0.5984 g. When it is dissolved in water and all its chlorine is converted to insoluble AgCl by addition of an excess of silver nitrate, the mass of the resulting AgCl is found to be 1.2756 g. The chemical reaction is (a) Calculate the formula mass of XCI₂. (b) Calculate the atomic mass of X. XCI2+ 2 AgNO3 Formula mass XCl₂ = Atomic mass X = 2AgCl + X(NO3)₂ g mol-1 g mol-1

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A sample of a substance with the empirical formula XCl₂ weighs 0.5984 g. When it is dissolved in water and all its
chlorine is converted to insoluble AgCl by addition of an excess of silver nitrate, the mass of the resulting AgCl is found
to be 1.2756 g. The chemical reaction is
(a) Calculate the formula mass of XCI2.
(b) Calculate the atomic mass of X.
XCI2+2 AgNO3 →2AgCl + X(NO3)₂
Formula mass XCI₂ =
Atomic mass X =
g mol-1
g mol-1
Transcribed Image Text:A sample of a substance with the empirical formula XCl₂ weighs 0.5984 g. When it is dissolved in water and all its chlorine is converted to insoluble AgCl by addition of an excess of silver nitrate, the mass of the resulting AgCl is found to be 1.2756 g. The chemical reaction is (a) Calculate the formula mass of XCI2. (b) Calculate the atomic mass of X. XCI2+2 AgNO3 →2AgCl + X(NO3)₂ Formula mass XCI₂ = Atomic mass X = g mol-1 g mol-1
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