A sample of a substance with the empirical formula XBrą weighs 0.5761 g. When it is dissolved in water and all its bromine is converted to insoluble AgBr by addition of an excess of silver nitrate, the mass of the resulting AgBr is found to be 1.0034 g. The chemical reaction is (a) Calculate the formula mass of XBr₂. (b) Calculate the atomic mass of X. XBr₂ + 2 AgNO3 +2AgBr + X(NO3)₂ Formula mass XBr₂ Atomic mass X= g mol-1 8 mot

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A sample of a substance with the empirical formula XBr₂ weighs 0.5761 g. When it is dissolved in water and all its bromine is
converted to insoluble AgBr by addition of an excess of silver nitrate, the mass of the resulting AgBr is found to be 1.0034 g. The
chemical reaction is
(a) Calculate the formula mass of XBr2.
(b) Calculate the atomic mass of X.
XBr₂ + 2 AgNO3 +2AgBr + X(NO3)₂
Formula mass XBr2 =
Atomic mass X=
& mol-1
8 mol-1
Transcribed Image Text:A sample of a substance with the empirical formula XBr₂ weighs 0.5761 g. When it is dissolved in water and all its bromine is converted to insoluble AgBr by addition of an excess of silver nitrate, the mass of the resulting AgBr is found to be 1.0034 g. The chemical reaction is (a) Calculate the formula mass of XBr2. (b) Calculate the atomic mass of X. XBr₂ + 2 AgNO3 +2AgBr + X(NO3)₂ Formula mass XBr2 = Atomic mass X= & mol-1 8 mol-1
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