Answered: If 23.3 grams of an aqueous solution of…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

If 23.3 grams of an aqueous solution of manganese(II) sulfate, MnSO₄, contains 5.96 grams of manganese(II) sulfate, what is the percentage by mass of manganese(II) sulfate in the solution?

Expert Solution

Step 1

Percentage by mass – ratio of Mass of solute to the Mass of solution and multiplied by 100 is percentage by mass.

Formula is,

$% b y m a s s = \frac{M a s s o f s o l u t e}{M a s s o f s o l u t i o n} \times 100$

Step 2

Answer of given numerical:

Given is that,

Mass of solute = 5.96 g

Mass of solution = 23.3 g

Now,

$P e r c e n t a g e b y m a s s = \frac{M a s s o f s o l u t e}{M a s s o f s o l u t i o n} \times 100 ∴ P e r c e n t a g e b y m a s s = \frac{5.96 g}{23.3 g} \times 100 ∴ P e r c e n t a g e b y m a s s = 25.579 %$

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