A reagent of known concentration that is often placed inside a buret titrant Chemicals are sold and classified based on their % purity. Arrange the following classifications according to increasing % purity. 1. Chemically pure (CP) II. Primary standard III. Reagent-grade a. l< ll
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- Please answer all parts4Ammonium sulfate is added to an unknown mixture of ions. A precipitate forms. The solution is centrifuged, and the remaining solutions is decanted. Ammonium oxalate is then added to the solution and no precipitate forms. Sodium monohydrogen phosphate and sodium hydroxide are added to the decanted solution, and no precipitate forms. Sodium hydroxide is added to a fresh sample of the unknown. A damp piece of litmus paper over the opening of the test tube turns blue. Select the ions present. Question 4 options: Ba2+ Ca2+ Mg2+ NH41+
- Ammonium sulfate is added to an unknown mixture of ions. A precipitate forms. The solution is centrifuged, and the remaining solutions is decanted. Ammonium oxalate is then added to the solution and no precipitate forms. Sodium monohydrogen phosphate and sodium hydroxide are added to the decanted solution, and no precipitate forms. Sodium hydroxide is added to a fresh sample of the unknown. A damp piece of litmus paper over the opening of the test tube remains red. Select the ions present. Question 5 options: Ba2+ Ca2+ Mg2+ NH41+Part A, B, and CAt 0 oC, the solubility of sodium acetate in water is 36.1 g per 100 g of water and at 40 oC, the solubility is 66.4 g per 100 g of water. A 100 g sample of sodium acetate is dissolved in 250 g of water at 40 °C. The solution is cooled to 0 °C and a small amount of solid is observed. This solution is ________. - hydrated -saturated -supersaturated - unsaturated
- 7 Solid lead (II) nitrate is slowly added to 125 mL of a 0.190 M potassium hydroxide solution until the concentration of lead ion is 0.0547 M. The percent of hydroxide ion remaining in solution is %. Submit Answer $ 4 R LLO % 5 [Review Topics) [References Use the References to access important values if needed for this question. Retry Entire Group T Cengage Learning | Cengage Technical Support ^ 6 * 8 more group attempts remaining MacBook Pro G H 2 & 7 A J * 0 8 ( 9 UD U K F 0 ) O ◆ P | Previous Email Instructor { [ + 11 = Next> Save and Exit } ]Talysis Google... M Inbox (684) - dian... Ed Edfinancial || Acco... о UTA email Free Biology 2e Te... canvas In-Class - Aktiv C... Question 2 of 17 If you have 155 mL solution of a 0.762 M FeCl solution, how many moles of FeCl are contained in this sample? 3 ADD FACTOR x() = ANSWER 7 RESET D< Week 8-1 X Week 8-1 X C 2 https://app.101edu.co K Formula Bara | PDF: SIF: Caf + 1 - 131 Sunny A Z "7 S ALEKS-13 x A ALEKS-Ti A ALEKS-TX Week 8-1 X m X Ksp 1.7 x 10. 36 x 10 - 4.3 x 10 3.5 x 10- x - Exam No.: x co DESU Calc X(427) mam xLog In | Fe x # Q Search Question 8 of 16 Which of the following salts would have the greatest solubility in water? _____________ __________ S L hp الالا alt A) BaF₂ B) PbF₂ C) SrF₂ D) CaF₂ ال A ctri لا pause < G Aktiv Chen a backspace X ● ه به enter GWhich oft X+ 3 T ما دیا ... T shift end 1 7 home 1 A ے h 1:0
- + I| P. * C0 ** w/ Table 3. Heat of neutralization data and calculations Table view List view Sample 1 [1] Volume of HCI (mL) Sample 2 (2) Temperature of HCI (mL) 6'6 24.0 [3] Volume of NAOH (mL) 24.2 49.8 [4] Temperature of mixture after reaction ("C) 6'6 31.0 Temperature difference (*C) 6'08 [5] Number of calories evolved (cal) enter a positive value (6] Moles of H* that were (jow) pazijennau [7] Calories evolved per mole of (jou/je) „H (2pts) Average of the two trials of calories evolved per mole of H (7pts) Part B. Enthalpy of Solution of Salts Table 4 Enthalny of solution of salts data andcalculations MacBook Air 08 DO #3 3 F8 24 2. % OL1 4. * 5. 9. 8 7. R. dele D. F. C. W command puDwwoɔ optionBelow you will find five reaction products (labeled product 1, product 2, etc.), but you will only find four reaction schemes. Your job is to match the reaction scheme with the correct product. Simply fill in the blank with the product number (i.e. 1,2,3,4, or 5). Then, state the regio-control that governs the reaction (i.e. Markovnikov or anti-Markovnikov). If the reaction does not have any regio-control then enter none. OH X Product 1 iocontrol: Product 2 1. Hg(OAc)2, H₂O 2. NaBH4 $ -OH do % Product 3 OH to 4- Product 4 OH OH Product 5 700 hpd. All of these. 9. Concentration of the stock solution is 0.30m. Howmuch of it would have to be diluted to the totAl of 10:00ml to get the conc of O. 0005m? a) n ml b) 17 microL c)17 mol