A reagent of known concentration that is often placed inside a buret titrant Chemicals are sold and classified based on their % purity. Arrange the following classifications according to increasing % purity. 1. Chemically pure (CP) II. Primary standard III. Reagent-grade a. l< ll
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- 1. Molarity of the NaOH solution 0.238 mol/L Trial 1 Trial 2 Trial 2. Volume of H;PO4 added to flask 22.0 mL 22.0 mL 22.0 mL 3. Initial NaOH volume _0.25_ mL _0.75_ mL 0.55 mL 4. Final NaOH volume 17.60_ mL 18.20_ mL _17.90_ mL 5. NAOH volume used for titration to reach green end point mL mL mL 6. NaOH volume used for titration 7. Moles of NaOH used for titration mol mel mel 8. Moles of H;PO4 that reacted mol mel mol 9. Volume of H;PO4 added to flask L 10. Molarity of H3PO4 mol/L mol/L mol/Lo/index.html?deploymentld%=55750828934189288909969212&eiSBN=9781305657571&snapshotld%32199898&id%3... ☆ IDTAP Q Search this cou Use the References to access important values if needed for this question. The concentration of H3ASO3 in a solution is determined by titration with a 0.1945 M Ce+ solution. The balanced net ionic equation for the reaction is: 2Ce*(aq) + H3ASO3(aq) + 5H2O(1) 2Ce*(aq) + H3ASO4(aq) + 2H3O*(aq) (a) If 19.83 mL of the 0.1945 M Ce** solution are needed to react completely with 30.00 mL of the H3ASO3 solution, what is the concentration of the H3ASO3 solution? M (b) Which of the two solutions was in the buret during the titration? (c) Suppose at the end of the titration, the solution containing the Ce³* ion is transferred to a volumetric flask and diluted to 300. mL. What is the concentration of Ce3+In the diluted solution? Submit Answer 5 question attempts remainingPlease answer all parts
- 45. From the stock solutions of 1.00-mol L acetic acid and 1.00-mol L of sodium acetate, six solutions were prepared with the acetic acid and acetate concentrations shown in the table below. The pk of acetic acid is 4.756. [Acetic acid). [Acetate). Final volume, Solutio mol L mol L ml A. 0.10 100 0.0000351 100 0.10 0.10 100 0.010 0.010 100 0.10 0.15 100 0.15 0.10 100 -1 Determine the volume of the stock solutions of 1.00-mol Lacetic acid and 1.00-mol L of sodium acetate needed to prepare the solutions. Write your answer in the table below. a. Vol. acetic acid, ml Vol. of acetate, ml Solution A b. Calculate for the initial pH of the solutions and write the pH in the table below. Solution Initial pH A Which solution(s) have the same pH? C.Ammonium sulfate is added to an unknown mixture of ions. A precipitate forms. The solution is centrifuged, and the remaining solutions is decanted. Ammonium oxalate is then added to the solution and no precipitate forms. Sodium monohydrogen phosphate and sodium hydroxide are added to the decanted solution, and no precipitate forms. Sodium hydroxide is added to a fresh sample of the unknown. A damp piece of litmus paper over the opening of the test tube turns blue. Select the ions present. Question 4 options: Ba2+ Ca2+ Mg2+ NH41+
- Ammonium sulfate is added to an unknown mixture of ions. A precipitate forms. The solution is centrifuged, and the remaining solutions is decanted. Ammonium oxalate is then added to the solution and no precipitate forms. Sodium monohydrogen phosphate and sodium hydroxide are added to the decanted solution, and no precipitate forms. Sodium hydroxide is added to a fresh sample of the unknown. A damp piece of litmus paper over the opening of the test tube remains red. Select the ions present. Question 5 options: Ba2+ Ca2+ Mg2+ NH41+B. Molar Concentration of an Acid Solution Acid type, HA or H,A: HA Unknown No. Balanced equation for neutralization of acid with NaOH. NaOH + HCI = NaCI + Sample 1 Sample 2 Sample 3 1. Volume of acid solution (mL) 25.0 25.0 25.0 2. Buret reading of NaOH, initial (mL) 0.00 0.00 0.00 3. Buret reading of NaOH, final (mL) 26.3 26.0 26.8 26.3 26.0 0.148 4. Volume of NaOH dispensed (mL) 26.8 5. Molar concentration of NAOH (mol/L), Part A 6. Moles of NaOH dispensed (mol) 7. Molar concentration of acid solution (mol/L) 8. Average molar concentration of acid solution (mol/L) Data Analysis, B 9. Standard deviation of molar concentration Data Analysis, C 10. Relative standard deviation of molar concentration (%RSD) Data Analysis, DPlease help me
- 2 Trial 1: [4] Volume of NaOH, dispensed (mL) Trial 1: [5] Molar concentration of NaOH (mol/L) Trial 2: [4] Volume of NaOH, dispensed (mL) How Trial 2: [5] Molar concentration of NaOH (mol/L) Trial 3: [4] Volume of NaOH, dispensed (mL) Trial 3: [5] Molar concentration of NaOH (mol/L)Solubility data of a sample is given below: Solvent Solubility in Cold Solvent Solubility in Hot Solvent Toluene Insoluble Soluble Dichloromethane Insoluble Insoluble Methanol Soluble Soluble From the above list, which solvent is bes ited for recrystallization this sample? Select one: Toluene Dichloromethane Methanol O Cannot be determined.Part II: Titration of Vinegar with Standaralzed Naun Report Table AV.4: Part 2 Calculations. Data and Calculations for three trials Part II: Titration of Vinegar with Standardized auη Report Table AV.4: Part 2 Calculations Data and Calculations for three trials Table view List view Trial 1 Trial 2 Trial 3 Volume of Vinegar Titrated (mL) 10.00 10.00 10.00 Initial Buret Reading (mL) 4.00 13.20 23.10 Final Buret Reading (mL) 13.20 23.10 34.001 9.20. 10.10 10.90 Volume NaOH used (mL) Moles Acetic Acid (mol) Mass Acetic Acid (g) Mass Percent Acetic Acid (%)