A potential difference V is applied to a wire of cross sectional area A, length L, and resistivity p. You want to change the applied potential difference and stretch the wire so that the energy dissipation rate is multiplied by 38.0 and the current is multiplied by 4.65. Assuming the wire's density does not change, what are (a) the ratio of the new length to L and (b) the ratio of the new cross-sectional area to A? (a) Number (b) Number Units Units

icon
Related questions
Question
A potential difference Vis applied to a wire of cross sectional area A, length L, and resistivity p. You want to change the applied
potential difference and stretch the wire so that the energy dissipation rate is multiplied by 38.0 and the current is multiplied by 4.65.
Assuming the wire's density does not change, what are (a) the ratio of the new length to L and (b) the ratio of the new cross-sectional
area to A?
(a) Number i
(b) Number i
Units
Units
Transcribed Image Text:A potential difference Vis applied to a wire of cross sectional area A, length L, and resistivity p. You want to change the applied potential difference and stretch the wire so that the energy dissipation rate is multiplied by 38.0 and the current is multiplied by 4.65. Assuming the wire's density does not change, what are (a) the ratio of the new length to L and (b) the ratio of the new cross-sectional area to A? (a) Number i (b) Number i Units Units
Expert Solution
steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Similar questions