Figure a shows a rod of resistive material. The resistance per unit length of the rod increases in positive direction of the X axis. At any position along the rod, the resistance dR of a narrow- differential-section of width dx is given by dR 5.00xdx, where dR is in ohms and a in meters. Figure b shows such a narrow section. You are to slice off a length of the rod between X = O and some position = L and then connect that length to a battery with potential difference V = 5.0V (Fig. c). You want the current in the length to transfer energy to therma energy at the rate of 6.2 W. At what position x = L in meters should you cut the rod? Keep decimla points in your aanswer. = dx 1.0 -x (m)

Figure a shows a rod of resistive material. The resistance per unit length of the rod increases in positive direction of the X axis. At any position along the rod, the resistance dR of a narrow- differential-section of width dx is given by dR 5.00xdx, where dR is in ohms and a in meters. Figure b shows such a narrow section. You are to slice off a length of the rod between X = O and some position = L and then connect that length to a battery with potential difference V = 5.0V (Fig. c). You want the current in the length to transfer energy to therma energy at the rate of 6.2 W. At what position x = L in meters should you cut the rod? Keep decimla points in your aanswer. = dx 1.0 -x (m)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Figure a shows a rod of resistive material. The
resistance per unit length of the rod increases in the
positive direction of the X axis. At any position x
along the rod, the resistance dR of a narrow-
differential-section of width dx is given by
dR = 5.00xdx, where dR is in ohms and is
in meters. Figure b shows such a narrow section.
You are to slice off a length of the rod between
X = O and some position = L and then
connect that length to a battery with potential
difference V = 5.0V (Fig. c). You want the
current in the length to transfer energy to thermal
energy at the rate of 6.2 W. At what position
x = L in meters should you cut the rod? Keep 2
decimla points in your aanswer.
dx
1.0
-x (m)

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