A poll of 2,030 randomly selected adults showed that 91​% of them own cell phones. The technology display below results from a test of the claim that 92​% of adults own cell phones. Use the normal distribution as an approximation to the binomial​ distribution, and assume a 0.05 significance level to complete parts​ (a) through​ (e).  Test of p=0.92 vs p≠0.92 Sample X N Sample p ​95% CI ​Z-Value ​P-Value 1 1855 2,030 0.913793 ​(0.901584​,0.926003​) −1.03 0.303 a. Is the test​ two-tailed, left-tailed, or​ right-tailed? Left-tailed test ​Two-tailed test Right tailed test   b. What is the test​ statistic? The test statistic is nothing. ​(Round to two decimal places as​ needed.)   c. What is the​ P-value? The​ P-value is . ​(Round to three decimal places as​ needed.)   d. What is the null hypothesis and what do you conclude about​ it? Identify the null hypothesis. A. H0: p>0.92 B. H0: p<0.92 C. H0: p=0.92 D. H0: p≠0.92   Choose the correct answer below.   A. Reject the null hypothesis because the​ P-value is less than or equal to the significance​ level, α. B. Fail to reject the null hypothesis because the​ P-value is greater than the significance​ level, α. C. Fail to reject the null hypothesis because the​ P-value is less than or equal to the significance​ level, α. D. Reject the null hypothesis because the​ P-value is greater than the significance​ level,α.     e. What is the final​ conclusion? A.Thereis not sufficient evidence to warrant rejection of the claim that 92​% of adults own a cell phone. B. There is notsufficient evidence to support the claim that 92​% of adults own a cell phone. C. There is sufficient evidence to support the claim that 92​% of adults own a cell phone D. There is sufficient evidence to warrant rejection of the claim that 92​% of adults own a cell phone.

MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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A poll of 2,030 randomly selected adults showed that 91​% of them own cell phones. The technology display below results from a test of the claim that
92​% of adults own cell phones. Use the normal distribution as an approximation to the binomial​ distribution, and assume a 0.05
significance level to complete parts​ (a) through​ (e). 
Test of
p=0.92
vs
p≠0.92
Sample
X
N
Sample p
​95% CI
​Z-Value
​P-Value
1
1855
2,030
0.913793
​(0.901584​,0.926003​)
−1.03
0.303
a. Is the test​ two-tailed, left-tailed, or​ right-tailed?
Left-tailed test
​Two-tailed test
Right tailed test
 
b. What is the test​ statistic?
The test statistic is nothing.
​(Round to two decimal places as​ needed.)
 
c. What is the​ P-value?
The​ P-value is .
​(Round to three decimal places as​ needed.)
 
d. What is the null hypothesis and what do you conclude about​ it?
Identify the null hypothesis.
A. H0: p>0.92
B. H0: p<0.92
C. H0: p=0.92
D. H0: p≠0.92
 
Choose the correct answer below.
 
A. Reject the null hypothesis because the​ P-value is less than or equal to
the significance​ level, α.
B. Fail to reject the null hypothesis because the​ P-value is greater than the significance​ level, α.
C. Fail to reject the null hypothesis because the​ P-value is less than or equal to the significance​ level, α.
D. Reject the null hypothesis because the​ P-value is greater than the significance​ level,α.
 
 
e. What is the final​ conclusion?
A.Thereis not sufficient evidence to warrant rejection of the claim that
92​% of adults own a cell phone.
B. There is notsufficient evidence to support the claim that 92​% of adults own a cell phone.
C. There is sufficient evidence to support the claim that 92​% of adults own a cell phone
D. There is sufficient evidence to warrant rejection of the claim that 92​%
of adults own a cell phone.

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