A poll of 2,079 randomly selected adults showed that 90% of them own cell phones. The technology display below results from a test of the claim that 93% of adults own cell phones Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p=0.93 vs p 0.93 Sample X N 2,079 1 1876 Sample p 0.902357 95% CI b. What is the test statistic? The test statistic is (Round to two decimal places as needed.) c. What is the P-value? (089597,0.915116) a. is the test two-tailea, lert-tailea, or rignt-talled? O Right tailed test O Left-tailed test OTwo-tailed test The P-value is (Round to three decimal places as needed.) d. What is the null hypothesis and what do you conclude about it? Z-Value - 4.94 P.Value 0.000 C...

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A poll of 2,079 randomly selected adults showed that 90% of them own cell phones. The technology display below results from a test of the claim that 93% of adults own cell phones.
Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e).
Test of p=0.93 vs p 0.93
Sample X
1
N
2,079
1876
Sample p
0.902357
95% CI
Z-Value
(089597,0.915116) - 4.94
a. is the test two-talled, left-talled, or rignt-talled?
O Right tailed test
O
Left-tailed test
OTwo-tailed test
b. What is the test statistic?
The test statistic is
(Round to two decimal places as needed.)
c. What is the P-value?
The P-value is
(Round to three decimal places as needed.)
d. What is the null hypothesis and what do you conclude about it?
13--66 LLLLL
P-Value
0.000
…...
Transcribed Image Text:A poll of 2,079 randomly selected adults showed that 90% of them own cell phones. The technology display below results from a test of the claim that 93% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p=0.93 vs p 0.93 Sample X 1 N 2,079 1876 Sample p 0.902357 95% CI Z-Value (089597,0.915116) - 4.94 a. is the test two-talled, left-talled, or rignt-talled? O Right tailed test O Left-tailed test OTwo-tailed test b. What is the test statistic? The test statistic is (Round to two decimal places as needed.) c. What is the P-value? The P-value is (Round to three decimal places as needed.) d. What is the null hypothesis and what do you conclude about it? 13--66 LLLLL P-Value 0.000 …...
A poll of 2,079 randomly selected adults showed that 90% of them own cell phones. The technology display below results from a test of the claim that 93% of adults own cell phones.
Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e).
Test of p=0.93 vs p *0.93
Sample X
1
N
2,079
1876
Sample p
0.902357
95% CI
(0.889597,0.915116)
Z-Value
-4.94
P-Value
0.000
RECEN
Choose the correct answer below.
O A. Reject the null hypothesis because the P-value is less than or equal to the significance level, a
OB. Fail to reject the null hypothesis because the P-value is greater than the significance level, a
OC. Reject the null hypothesis because the P-value is greater than the significance level, c.
OD. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a
e. What is the final conclusion?
OA. There is sufficient evidence to support the claim that 93% of adults own a cell phone.
OB. There is sufficient evidence to warrant rejection of the claim that 93% of adults own a cell phone.
OC. There is not sufficient evidence to support the claim that 93% of adults own a cell phone.
O D. There is not sufficient evidence to warrant rejection of the claim that 93% of adults own a cell phone.
4
Transcribed Image Text:A poll of 2,079 randomly selected adults showed that 90% of them own cell phones. The technology display below results from a test of the claim that 93% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p=0.93 vs p *0.93 Sample X 1 N 2,079 1876 Sample p 0.902357 95% CI (0.889597,0.915116) Z-Value -4.94 P-Value 0.000 RECEN Choose the correct answer below. O A. Reject the null hypothesis because the P-value is less than or equal to the significance level, a OB. Fail to reject the null hypothesis because the P-value is greater than the significance level, a OC. Reject the null hypothesis because the P-value is greater than the significance level, c. OD. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a e. What is the final conclusion? OA. There is sufficient evidence to support the claim that 93% of adults own a cell phone. OB. There is sufficient evidence to warrant rejection of the claim that 93% of adults own a cell phone. OC. There is not sufficient evidence to support the claim that 93% of adults own a cell phone. O D. There is not sufficient evidence to warrant rejection of the claim that 93% of adults own a cell phone. 4
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