A poll of 2,188 randomly selected adults showed that 90% of them own cell phones. The technology display below resultsfrom a test of the claim that 94% of adults own cell phones. Use the normal distribution as an approximation to thebinomial distribution, and assume a 0.05 significance level to complete parts (a) through (e).Test of p = 0.94 vs p *0.94Sample XN12,1881969Sample p0.899909b. What is the test statistic?a. Is the test two-tailed, left-tailed, or right-tailed?Two-tailed testRight tailed testLeft-tailed testThe test statistic is -7.90 .(Round to two decimal places as needed.)c. What is the P-value?95% CIThe P-value is.(Round to three decimal places as needed.)(0.887333,0.912484)Z-Value- 7.90P-Value0.000

The question is about hypo. testingGiven :Test for p = 0.94 vs p ≠ 0.94z value = -7.90P value =…

Answered: A poll of 2,188 randomly selected…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The Australian sheep dog is a breed renowned for its intelligence and work ethic. It is estimated that 30% of adult Australian sheep dogs weigh 65 pounds (lbs) or more. A sample of 40 adult dogs is studied and follows a binomial distribution. Let X be a binomial random variable that represents the number of adult dogs in the sample who weigh 65 lb or more. a. Find the mean number of dogs in this sample who weigh 65 lb or more. Mean = b. Find the standard deviation of the number of dogs in the sample who weigh 65 lb or more. Round to three places. Standard deviation =
Before the furniture store began its ad campaign, it averaged 123 customers per day. The manager is investigating if the average is larger since the ad came out. The data for the 11 randomly selected days since the ad campaign began is shown below: 110, 154, 108, 112, 151, 146, 144, 130, 138, 129, 142 Assuming that the distribution is normal, what can be concluded at the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: vSelect an answer H1: ?V Select an answer V c. The test statistic ? (please show your answer to 3 decimal places.) d. The p-value = e. The p-value is ?V a f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... (Please show your answer to 4 decimal places.) the null hypothesis. O The data suggest the populaton mean is significantly more than 123 at a = 0.05, so there is sufficient evidence to conclude that the population mean number of customers since the…
The accompanying table gives results from a study of words spoken in a day by men and women. Assume that both samples are independent simple random samples from populations having normal distributions. Use a 0.05 significance level to test the claim that the numbers of words spoken in a day by men vary more than the numbers of words spoken in a day by women. n X S Men Women 185 211 15,667.8 16,215.3 8,632.7 7,301.6 What are the null and alternative hypotheses? OA. Ho₂:0² #0²₂2 B. H₂:0² = 0²/2 H₁:0² > 0² H₁ : 0 ²₁2 = 0²/2 OC. H₂ : 0 ²₁2 = 0²/2 OD. H₂:0² = 0²/22 H₁:0² <0² H₁: : 0² / ± 0²/2 Identify the test statistic. F= (Round to two decimal places as needed.) Use technology to identify the P-value. The P-value is. (Round to three decimal places as needed.) What is the conclusion for this hypothesis test? O A. Reject Ho. There is insufficient evidence to support the claim that the numbers of words spoken in a day by men vary more than the numbers of words spoken in a day by women. B.…
The accompanying table gives results from a study of words spoken in a day by men and women. Assume that both samples are independent simple random samples from populations having normal distributions. Use a 0.05 significance level to test the claim that the numbers of words spoken in a day by men vary more than the numbers of words spoken in a day by women. n x s Men 185 15,667.8 8,632.5 Women 212 16,215.5 7,301.2 What are the null and alternative hypotheses? A. H0: σ21≠σ22 H1: σ21=σ22 B. H0: σ21=σ22 H1: σ21>σ22 C. H0: σ21=σ22 H1: σ21<σ22 D. H0: σ21=σ22 H1: σ21≠σ22 Identify the test statistic. F= (Round to two decimal places as needed.) Use technology to identify the P-value. The P-value is (Round to three decimal places as needed.) What is the conclusion for this hypothesis test? A.Reject H0. There is insufficient evidence to support the claim that…
The accompanying table gives results from a study of words spoken in a day by men and women. Assume that both samples are independent simple random samples from populations having normal distributions. Use a 0.05 significance level to test the claim that the numbers of words spoken in a day by men vary more than the numbers of words spoken in a day by women. n x s Men 187 15,668.9 8,632.2 Women 211 16,215.4 7,301.4 => Identify the test statistic. (Round to two decimal places as needed.) Use technology to identify the P-value. (Round to three decimal places as needed.) What is the conclusion for this hypothesis test? reject/fail to reject?
The accompanying data table lists the magnitudes of 50 earthquakes measured on the Richter scale. Test the claim that the population of earthquakes has a mean magnitude greater than 1.00. Use a 0.01 significance level. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, and conclusion for the test. Assume this is a simple random sample.
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A study reported that finger rings increase the growth of bacteria on health-care workers’ hands. Research suggests that 31 percent of health-care workers who wear rings have bacteria on one or both hands. Suppose that independent random samples of 100 health-care workers wearing rings is selected. What is the standard deviation of the sampling distribution of the sample proportions of health-care workers having bacteria on one or both hands? A. 100 B. 0.0462 C. 0.69
A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random. samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? OA. Ho: H1 H2 H₁₁₂ The test statistic, t, is (Round to two decimal places as needed.) OB. Ho: H₁₂ H₁: H₁
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