A poll of 2,146 randomly selected adults showed that 92% of them own cell phones. The technology display below results from a test of the claim that 94% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). Test of p = 0.94 vs p = 0.94 Sample X N 2,146 1 1976 Sample p 0.920783 Z-Value (0.905766,0.935800) -3.75 The P-value is (Round to three decimal places as needed.) 95% CI a. Is the test two-tailed, left-tailed, or right-tailed? O Right tailed test Two-tailed test O Left-tailed test b. What is the test statistic? The test statistic is. (Round to two decimal places as needed.) c. What is the P-value? P-Value 0.000

Q: Evaluate if x=4,8,3,-2 ∑x ∑x+1 ∑(x+1) 3∑x - 4

A: Given that  if x=4,8,3,-2

Q: Usiug the LAws of Logs/ NATUAL Logs O ExpAND: X*メー」 4 loyx + 2log(x-) - %log (2e+) 2x-3

A:

Q: . Show that if P(A) > 0, then P(AB|A) ≥ P(AB|A U B)

A:

Q: With each step show the rule associated with it

A:

Q: 8. Which expression is the simplest form of V48 – 4V6

A: Simplest form: - When an expression is easiest to employ, it is in its simplest form. Given: - The…

Q: If z = x* - 3x2 + 6x + 5y3- 7y + 7, find az az and ax ay az ax az ay

A:

Q: 2 excos2rdr / 2) 0

A:

Q: 48. -1 12 cos 2 tan-1 210

A: Topic - trigonometric identities We are given: cos2tan-1125Formulas requiredcos(2θ)=1-tan2θ1+tan2θ

Q: -2 23 3 in span Is {} 2 3 1 1

A:

Q: 6 -1 Let A= Find-3A. 3 -7 -3A =|

A:

Q: Hello, can you help me out with this problem? Please write a solution on a piece of paper and upload…

A:

Q: 6. Which expression is the simplest form of V12+ V48

A: Solution

Q: Pleae Sotve the integet X+)V2a+1

A:

Q: Find Jul, Ivl, 12u[, , lu + vl, lu - vl, and Jul - Ivl. u - (1, -4), v= (-10, –10)

A:

Q: VI - Ja lim

A: We rationalize the numerator

Q: Solve the following recurrence relation with the given initial condition: an = (n + 1)a,n-1 for n =…

A:

Q: Let A = {h,1,o}, B = {7,8), C = {7}. AXBXC = { CXBXA = { BXBXB={

A: