A poll of 2,063 randomly selected adults showed that 95% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). Test of p = 0.92 vs p#0.92 Sample X N Sample p 95% CI Z-Value P-Value 1 1965 2,063 0.952496 (0.940433,0.964560) 5.44 0.000 ..... a. Is the test two-tailed, left-tailed, or right-tailed? Left-tailed test Two-tailed test O Right tailed test b. What is the test statistic? The test statistic is. (Round to two decimal places as needed.) c. What is the P-value? The P-value is (Round to three decimal places as needed.) d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis. O A. Ho: p= 0.92 O B. Ho: p+0.92 OC. Ho: p<0.92

MATLAB: An Introduction with Applications
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A poll of 2,063 randomly selected adults showed that 95% of them own cell phones. The technology display below results from a test of the claim that 92% of adults
own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e).
Test of p = 0.92 vs p+0.92
Sample
N
Sample p
95% CI
Z-Value
P-Value
1
1965
2,063
0.952496
(0.940433,0.964560)
5.44
0.000
.....
a. Is the test two-tailed, left-tailed, or right-tailed?
Left-tailed test
Two-tailed test
Right tailed test
b. What is the test statistic?
The test statistic is
(Round to two decimal places as needed.)
c. What is the P-value?
The P-value is.
(Round to three decimal places as needed.)
d. What is the null hypothesis and what do you conclude about it?
Identify the null hypothesis.
О А. Но: р30.92
В. Но: р#0.92
О с. Но: р<0.92
Transcribed Image Text:A poll of 2,063 randomly selected adults showed that 95% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). Test of p = 0.92 vs p+0.92 Sample N Sample p 95% CI Z-Value P-Value 1 1965 2,063 0.952496 (0.940433,0.964560) 5.44 0.000 ..... a. Is the test two-tailed, left-tailed, or right-tailed? Left-tailed test Two-tailed test Right tailed test b. What is the test statistic? The test statistic is (Round to two decimal places as needed.) c. What is the P-value? The P-value is. (Round to three decimal places as needed.) d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis. О А. Но: р30.92 В. Но: р#0.92 О с. Но: р<0.92
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