A poll of 2,130 randomly selected adults showed that 94% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p=0.92 vs p#0.92 Sample X Sample p 95% CI Z-Value P.Value 1992 2,130 0.935211 (0.924758,0.945665) 2.59 0.010 a. Is the test two-tailed, left-tailed, or right-tailed? Two-tailed test Right tailed test Left-tailed test b. What is the test statistic? The test statistic is. (Round to two decimal places as needed.) c. What is the P-value? The P-value is (Round to three decimal places as needed.) Click to select your answer(s).
A poll of 2,130 randomly selected adults showed that 94% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p=0.92 vs p#0.92 Sample X Sample p 95% CI Z-Value P.Value 1992 2,130 0.935211 (0.924758,0.945665) 2.59 0.010 a. Is the test two-tailed, left-tailed, or right-tailed? Two-tailed test Right tailed test Left-tailed test b. What is the test statistic? The test statistic is. (Round to two decimal places as needed.) c. What is the P-value? The P-value is (Round to three decimal places as needed.) Click to select your answer(s).
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![A poll of 2,130 randomly selected adults showed that 94% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal
distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e).
Test of p= 0.92 vs p#0.92
Sample X
N.
Sample p
95% CI
z-Value
P-Value
1992
2,130
0.935211
(0.924758,0.945665) 2.59
0.010
d. What is the null hypothesis and what do you conclude about it?
Identify the null hypothesis.
O A. Ho: p>0.92
O B. Ho: p=0.92
O C. Ho: p<0.92
O D. Ho: p#0.92
Choose the correct answer below.
O A. Reject the null hypothesis because the P-value is greater than the significance level, a.
O B. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.
O C. Reject the null hypothesis because the P-value
s less than or equal to the significance level, a.
Click to select your answer(s).
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Transcribed Image Text:A poll of 2,130 randomly selected adults showed that 94% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal
distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e).
Test of p= 0.92 vs p#0.92
Sample X
N.
Sample p
95% CI
z-Value
P-Value
1992
2,130
0.935211
(0.924758,0.945665) 2.59
0.010
d. What is the null hypothesis and what do you conclude about it?
Identify the null hypothesis.
O A. Ho: p>0.92
O B. Ho: p=0.92
O C. Ho: p<0.92
O D. Ho: p#0.92
Choose the correct answer below.
O A. Reject the null hypothesis because the P-value is greater than the significance level, a.
O B. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.
O C. Reject the null hypothesis because the P-value
s less than or equal to the significance level, a.
Click to select your answer(s).
Show
A Persuasive Spee.doc
a PersuasiveSpch.doc
2 SamplePPTforP.pptx
> Persuasive Spe.docx
étv
MacBook Air
F9
20
F3
esc
F1
*
&
$
9
@
6
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W
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![A poll of 2,130 randomly selected adults showed that 94% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal
distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e).
Test of p= 0.92 vs p#0.92
Sample X
Sample p
95% CI
1
Z-Value
P-Value
1992
2,130
0.935211
(0.924758,0.945665) 2.59
0.010
a. Is the test two-tailed, left-tailed, or right-tailed?
Two-tailed test
O Right tailed test
O Left-tailed test
b. What is the test statistic?
The test statistic is.
(Round to two decimal places as needed.)
c. What is the P-value?
The P-value is
(Round to three decimal places as needed.)
Click to select your answer(s).
Show All
a
PersuasiveSpch..doc
2 SamplePPTforP..pptx
a Persuasive Spe.docx
a Persuasive Spee.doc
étv
W
MacBook Air
F10
F9
FB
F7
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F4
F6
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esc
F1
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$
9
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4
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1
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R](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffd93e1a4-6168-4d15-ae62-a31531410aae%2F44a08fb2-a9ff-4e4c-b8e1-98880118c8f1%2Fkpcycll_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A poll of 2,130 randomly selected adults showed that 94% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal
distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e).
Test of p= 0.92 vs p#0.92
Sample X
Sample p
95% CI
1
Z-Value
P-Value
1992
2,130
0.935211
(0.924758,0.945665) 2.59
0.010
a. Is the test two-tailed, left-tailed, or right-tailed?
Two-tailed test
O Right tailed test
O Left-tailed test
b. What is the test statistic?
The test statistic is.
(Round to two decimal places as needed.)
c. What is the P-value?
The P-value is
(Round to three decimal places as needed.)
Click to select your answer(s).
Show All
a
PersuasiveSpch..doc
2 SamplePPTforP..pptx
a Persuasive Spe.docx
a Persuasive Spee.doc
étv
W
MacBook Air
F10
F9
FB
F7
888
F4
F6
F5
F2
esc
F1
*
&
$
9
@
#
4
5
2
3
1
E
R
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