A poll of 2,130 randomly selected adults showed that 94% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p=0.92 vs p#0.92 Sample X Sample p 95% CI Z-Value P.Value 1992 2,130 0.935211 (0.924758,0.945665) 2.59 0.010 a. Is the test two-tailed, left-tailed, or right-tailed? Two-tailed test Right tailed test Left-tailed test b. What is the test statistic? The test statistic is. (Round to two decimal places as needed.) c. What is the P-value? The P-value is (Round to three decimal places as needed.) Click to select your answer(s).

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A poll of 2,130 randomly selected adults showed that 94% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal
distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e).
Test of p= 0.92 vs p#0.92
Sample X
N.
Sample p
95% CI
z-Value
P-Value
1992
2,130
0.935211
(0.924758,0.945665) 2.59
0.010
d. What is the null hypothesis and what do you conclude about it?
Identify the null hypothesis.
O A. Ho: p>0.92
O B. Ho: p=0.92
O C. Ho: p<0.92
O D. Ho: p#0.92
Choose the correct answer below.
O A. Reject the null hypothesis because the P-value is greater than the significance level, a.
O B. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.
O C. Reject the null hypothesis because the P-value
s less than or equal to the significance level, a.
Click to select your answer(s).
Show
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Transcribed Image Text:A poll of 2,130 randomly selected adults showed that 94% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p= 0.92 vs p#0.92 Sample X N. Sample p 95% CI z-Value P-Value 1992 2,130 0.935211 (0.924758,0.945665) 2.59 0.010 d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis. O A. Ho: p>0.92 O B. Ho: p=0.92 O C. Ho: p<0.92 O D. Ho: p#0.92 Choose the correct answer below. O A. Reject the null hypothesis because the P-value is greater than the significance level, a. O B. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. O C. Reject the null hypothesis because the P-value s less than or equal to the significance level, a. Click to select your answer(s). Show A Persuasive Spee.doc a PersuasiveSpch.doc 2 SamplePPTforP.pptx > Persuasive Spe.docx étv MacBook Air F9 20 F3 esc F1 * & $ 9 @ 6 3 4 Y W E R Q K T
A poll of 2,130 randomly selected adults showed that 94% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal
distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e).
Test of p= 0.92 vs p#0.92
Sample X
Sample p
95% CI
1
Z-Value
P-Value
1992
2,130
0.935211
(0.924758,0.945665) 2.59
0.010
a. Is the test two-tailed, left-tailed, or right-tailed?
Two-tailed test
O Right tailed test
O Left-tailed test
b. What is the test statistic?
The test statistic is.
(Round to two decimal places as needed.)
c. What is the P-value?
The P-value is
(Round to three decimal places as needed.)
Click to select your answer(s).
Show All
a
PersuasiveSpch..doc
2 SamplePPTforP..pptx
a Persuasive Spe.docx
a Persuasive Spee.doc
étv
W
MacBook Air
F10
F9
FB
F7
888
F4
F6
F5
F2
esc
F1
*
&
$
9
@
#
4
5
2
3
1
E
R
Transcribed Image Text:A poll of 2,130 randomly selected adults showed that 94% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p= 0.92 vs p#0.92 Sample X Sample p 95% CI 1 Z-Value P-Value 1992 2,130 0.935211 (0.924758,0.945665) 2.59 0.010 a. Is the test two-tailed, left-tailed, or right-tailed? Two-tailed test O Right tailed test O Left-tailed test b. What is the test statistic? The test statistic is. (Round to two decimal places as needed.) c. What is the P-value? The P-value is (Round to three decimal places as needed.) Click to select your answer(s). Show All a PersuasiveSpch..doc 2 SamplePPTforP..pptx a Persuasive Spe.docx a Persuasive Spee.doc étv W MacBook Air F10 F9 FB F7 888 F4 F6 F5 F2 esc F1 * & $ 9 @ # 4 5 2 3 1 E R
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