A particular reactant molecule "R" is capable of undergoing condensation and forming either a single closed loop (R-> L) or long chain polymer (R+R+R ->P). The rate law for the loop forming reaction is rate(loop) = kLoop[R]; the rate lw for the polymerization reaction is rate(poly) = kpoly[R]^2 a) a beaker with a starting concentration of R equals 0.50M at 60degrees. After 75 minutes of reacting, the concentration of L is 0.10M. Assuming no change in volume or temperature, find k(loop) b. At the 75 minute mark the remaing concentration of R is 0.398M. What can you conclude (qualitatively) about the magnitude of k(poly) relative to k(loop)?
A particular reactant molecule "R" is capable of undergoing condensation and forming either a single closed loop (R-> L) or long chain polymer (R+R+R ->P). The rate law for the loop forming reaction is rate(loop) = kLoop[R]; the rate lw for the polymerization reaction is rate(poly) = kpoly[R]^2 a) a beaker with a starting concentration of R equals 0.50M at 60degrees. After 75 minutes of reacting, the concentration of L is 0.10M. Assuming no change in volume or temperature, find k(loop) b. At the 75 minute mark the remaing concentration of R is 0.398M. What can you conclude (qualitatively) about the magnitude of k(poly) relative to k(loop)?
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section: Chapter Questions
Problem 83QRT
Related questions
Question
100%
A particular reactant molecule "R" is capable of undergoing condensation and forming either a single closed loop (R-> L) or long chain
a) a beaker with a starting concentration of R equals 0.50M at 60degrees. After 75 minutes of reacting, the concentration of L is 0.10M. Assuming no change in volume or temperature, find k(loop)
b. At the 75 minute mark the remaing concentration of R is 0.398M. What can you conclude (qualitatively) about the magnitude of k(poly) relative to k(loop)?
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning