**Chlorine Dioxide Reaction Rate**Chlorine dioxide, \( \text{ClO}_2 \), is a reddish-yellow gas that is soluble in water. In basic solutions, it produces \( \text{ClO}_3^- \) and \( \text{ClO}_2^- \) ions.**Chemical Reaction:**\[ 2\text{ClO}_2\,(\text{aq}) + 2\text{OH}^-\,(\text{aq}) \rightarrow \text{ClO}_3^-\,(\text{aq}) + \text{ClO}_2^-\,(\text{aq}) + \text{H}_2\text{O}(\text{l}) \]To determine the rate law for this reaction, various experiments were conducted, measuring the initial concentration of reactants and the initial rate of reaction.**Experimental Data:**| Experiment | Initial Concentration of \( \text{ClO}_2 \) (mol/L) | Initial Concentration of \( \text{OH}^- \) (mol/L) | Initial Rate (mol/L·s) ||------------|---------------------------------|-------------------------------------|------------------------|| Exp. 1 | 0.21 | \(1.6 \times 10^{-2}\) | 0.162 || Exp. 2 | \(7.0 \times 10^{-2}\) | \(1.6 \times 10^{-2}\) | \(1.80 \times 10^{-2}\)|| Exp. 3 | \(7.0 \times 10^{-2}\) | \(4.8 \times 10^{-2}\) | \(5.39 \times 10^{-2}\)|**Objective:**(a) Obtain the rate law for the reaction using the experimental data. Use \( k \) for the rate constant.**Rate Law:** \[ \text{Rate} = k [\text{ClO}_2]^m [\text{OH}^-]^n \]To determine the specific values of \( m \) and \( n \), analyze the experimental data by observing how changes in concentrations affect the reaction rate.

The rate law of any reaction depends only on the reactant concentration at a constant temperature.…

Chlorine dioxide, Cl02, is a reddish-yellow gas that is soluble in water. In basic solution it gives Cl03 and Cl02 ions. 2C102 (ag) + 20H (ag) → ClO3 (ag) + C1O2¯(aq) + H20(1) To obtain the rate law for this reaction, the following experiments were run and, for each, the initial rate of reaction of C102 was determined. Initial Concentration Initial Concentration Initial Rate of C102 (mol/L) of OH (mo/L) (тol (L-)) Exp. 1 0.21 1.6 x 10-2 0.162 Exp. 2 7.0 × 10-2 1.6 x 10-2 1.80 x 10-2 Exp. 3 7.0 x 10-2 4.8 × 10-2 5.39 x 10-2 a Obtain the rate law. (Use k for the rate constant.) Rate law =

Chlorine dioxide, Cl02, is a reddish-yellow gas that is soluble in water. In basic solution it gives Cl03 and Cl02 ions. 2C102 (ag) + 20H (ag) → ClO3 (ag) + C1O2¯(aq) + H20(1) To obtain the rate law for this reaction, the following experiments were run and, for each, the initial rate of reaction of C102 was determined. Initial Concentration Initial Concentration Initial Rate of C102 (mol/L) of OH (mo/L) (тol (L-)) Exp. 1 0.21 1.6 x 10-2 0.162 Exp. 2 7.0 × 10-2 1.6 x 10-2 1.80 x 10-2 Exp. 3 7.0 x 10-2 4.8 × 10-2 5.39 x 10-2 a Obtain the rate law. (Use k for the rate constant.) Rate law =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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