Homework Help is Here – Start Your Trial Now!
Science
Chemistry
A mixture of pure BaCO3 and pure Na2CO3 weighs 1.000 g and has the total neutralizing power of 15.37 meq of CaCO3. Calculate the percentage of combined CO2 in the mixture and the weight of Li2CO3 that has the same neutralizing power as 1.000 g of the above mixture. Instructions: Include up to 4 decimal places See sample photo for the format of solution

A mixture of pure BaCO3 and pure Na2CO3 weighs 1.000 g and has the total neutralizing power of 15.37 meq of CaCO3. Calculate the percentage of combined CO2 in the mixture and the weight of Li2CO3 that has the same neutralizing power as 1.000 g of the above mixture. Instructions: Include up to 4 decimal places See sample photo for the format of solution

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
See similar textbooks
icon
Related questions
Question
A mixture of pure BaCO3 and pure Na2CO3 weighs 1.000 g and has the total neutralizing power of 15.37 meq of CaCO3. Calculate the percentage of combined CO2 in the mixture and the weight of Li2CO3 that has the same neutralizing power as 1.000 g of the above mixture. Instructions: Include up to 4 decimal places See sample photo for the format of solution
Determination of the Proportion in which Components are present in a mixture: Example: If 0.5000 g of a mixture of CaCO3 and BaCO3 requires 30.00 mL of a 0.2500N HCI for neutralization. What is the percentage of each component? let x = g CaCO3 and y=g BaCO3 x + y = 0.5000 → equation1 eq of CaCO3 present = X CaCO3/2 50.04 eq of BaCO3 present = = BaCO3/2 eq CaCO3 + eq BaCO3 = eq HCI sample sol'n + 50.04 98.69 Solving equations 1 and 2 simultaneously: x = 0.247 g y = 0.253 g % CaCO3 = [0.247/0.500) x 100 = 49.4% % BaCO3 = (0.253/0.500) x 100 = 50.6% Example: The weight of combined LIOH, KOH and Ba(OH)2 in a mixture is 0.5000 g and requires 25.43 mL of 0.500N acid for neutralization. The same weight of sample with CO₂ gives a precipitate of BaCO3 that requires 5.27 mL of the above acid for neutralization. Find the weights of LiOH, KOH and Ba(OH)2 in the original mixture. Let x = g LIOH and y = g KOH and z= g Ba(OH)2 X + y + z = 0.5000 → 1 eq LiOH = X eq Ba(OH)2 = Z 23.95/1 171.36/2 eq KOHV 56.11/1 eq LIOH + eq KOH + eq Ba(OH)2 = 25.43mL (0.5eq/L) 1000mL/L → equation 2 eq Ba(OH)2 = eq BaCO³ = 5.27 ml (0.5 eq/l) 1000mL/L wt Ba(OH)2 x 2 eq/mol = 2.635 x 10³ eq Sample Soln wt Ba(OH)2 = 0.2258 g X x + y = 0.2742 eq LIOH + eq KOH + eq Ba(OH)2 = 25.43mL[0.5eq/L) 1000mL/L → equation 2 eq LIOH + eq KOH +2.635 x 103 eq = 0.012715 eq X + y = 0.01008 23.95/1 56.11/1 Solving equations 1 and 2 simultaneously: x = 0.217 g y = 0.0572 g Question: A mixture of pure BaCO3 and pure Na₂CO3 weighs 1.000 g and has the total neutralizing power of 15.37 meq of CaCO3. Calculate the percentage of combined CO₂ in the mixture and the weight of Li₂CO3 that has the same neutralizing power as 1.000 g of the above mixture. 98.69 = 30.0 mL (0.250eq/L) (1000mL/L) → equation2 171.36 g/mol + y + 0.2258 0.5000 →1
Transcribed Image Text:Determination of the Proportion in which Components are present in a mixture: Example: If 0.5000 g of a mixture of CaCO3 and BaCO3 requires 30.00 mL of a 0.2500N HCI for neutralization. What is the percentage of each component? let x = g CaCO3 and y=g BaCO3 x + y = 0.5000 → equation1 eq of CaCO3 present = X CaCO3/2 50.04 eq of BaCO3 present = = BaCO3/2 eq CaCO3 + eq BaCO3 = eq HCI sample sol'n + 50.04 98.69 Solving equations 1 and 2 simultaneously: x = 0.247 g y = 0.253 g % CaCO3 = [0.247/0.500) x 100 = 49.4% % BaCO3 = (0.253/0.500) x 100 = 50.6% Example: The weight of combined LIOH, KOH and Ba(OH)2 in a mixture is 0.5000 g and requires 25.43 mL of 0.500N acid for neutralization. The same weight of sample with CO₂ gives a precipitate of BaCO3 that requires 5.27 mL of the above acid for neutralization. Find the weights of LiOH, KOH and Ba(OH)2 in the original mixture. Let x = g LIOH and y = g KOH and z= g Ba(OH)2 X + y + z = 0.5000 → 1 eq LiOH = X eq Ba(OH)2 = Z 23.95/1 171.36/2 eq KOHV 56.11/1 eq LIOH + eq KOH + eq Ba(OH)2 = 25.43mL (0.5eq/L) 1000mL/L → equation 2 eq Ba(OH)2 = eq BaCO³ = 5.27 ml (0.5 eq/l) 1000mL/L wt Ba(OH)2 x 2 eq/mol = 2.635 x 10³ eq Sample Soln wt Ba(OH)2 = 0.2258 g X x + y = 0.2742 eq LIOH + eq KOH + eq Ba(OH)2 = 25.43mL[0.5eq/L) 1000mL/L → equation 2 eq LIOH + eq KOH +2.635 x 103 eq = 0.012715 eq X + y = 0.01008 23.95/1 56.11/1 Solving equations 1 and 2 simultaneously: x = 0.217 g y = 0.0572 g Question: A mixture of pure BaCO3 and pure Na₂CO3 weighs 1.000 g and has the total neutralizing power of 15.37 meq of CaCO3. Calculate the percentage of combined CO₂ in the mixture and the weight of Li₂CO3 that has the same neutralizing power as 1.000 g of the above mixture. 98.69 = 30.0 mL (0.250eq/L) (1000mL/L) → equation2 171.36 g/mol + y + 0.2258 0.5000 →1
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Gravimetric Analysis
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
SEE MORE TEXTBOOKS