A student adds too much HCI during the titration. Will the calculated Ksp be too high, too low, or unaffected? Why? O Because the student is adding too much HCI, the calculated [H30*] will be too high. Since Kw = [H30*]· [OH¯], the implied [OH¯] will be too low, and because Kso = (1/2) x [OH ]3 the calculated Ksp value will be too low. O Ksp = (1/2) x [OH ]3 and since the [H30*] does not appear in that formula, the calculated Ksp value will be unaffected. O Because the student is adding too much HCI, the calculated [H30+] will be too high. Since H30* and OH- react in a 1:1 ratio, the implied [OH-] will be too high, and because Ksp = (1/2) x [OH-]3 the calculated Ksp value will be too high.
A student adds too much HCI during the titration. Will the calculated Ksp be too high, too low, or unaffected? Why? O Because the student is adding too much HCI, the calculated [H30*] will be too high. Since Kw = [H30*]· [OH¯], the implied [OH¯] will be too low, and because Kso = (1/2) x [OH ]3 the calculated Ksp value will be too low. O Ksp = (1/2) x [OH ]3 and since the [H30*] does not appear in that formula, the calculated Ksp value will be unaffected. O Because the student is adding too much HCI, the calculated [H30+] will be too high. Since H30* and OH- react in a 1:1 ratio, the implied [OH-] will be too high, and because Ksp = (1/2) x [OH-]3 the calculated Ksp value will be too high.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A student adds too much HCI during the titration. Will the calculated Ksp be too high, too low, or unaffected? Why?
Because the student is adding too much HCI, the calculated [H30+] will be too high. Since Kw = [H3o+]•[0H¯], the implied [OH¯] will be too low, and because Ksp
(1/2) x [OH-]³ the calculated Ksp value will be
too low.
Ksp = (1/2) x [OH¯]³ and since the [H30+] does not appear in that formula, the calculated Ksp value will be unaffected.
Because the student is adding too much HCI, the calculated [H30+] will be too high. Since H30+ and OH- react in a 1:1 ratio, the implied [OH-] will be too high, and because Ksp
(1/2) x [OH-]3 the calculated Ksp
value will be too high.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F668f7243-fecb-4dca-9846-a35dbaef67d8%2F00195afd-bc4e-465f-b5e8-e5c550cea95e%2Ff9frh7r_processed.png&w=3840&q=75)
Transcribed Image Text:A student adds too much HCI during the titration. Will the calculated Ksp be too high, too low, or unaffected? Why?
Because the student is adding too much HCI, the calculated [H30+] will be too high. Since Kw = [H3o+]•[0H¯], the implied [OH¯] will be too low, and because Ksp
(1/2) x [OH-]³ the calculated Ksp value will be
too low.
Ksp = (1/2) x [OH¯]³ and since the [H30+] does not appear in that formula, the calculated Ksp value will be unaffected.
Because the student is adding too much HCI, the calculated [H30+] will be too high. Since H30+ and OH- react in a 1:1 ratio, the implied [OH-] will be too high, and because Ksp
(1/2) x [OH-]3 the calculated Ksp
value will be too high.
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