A student adds too much HCI during the titration. Will the calculated Ksp be too high, too low, or unaffected? Why?Because the student is adding too much HCI, the calculated [H30+] will be too high. Since Kw = [H3o+]•[0H¯], the implied [OH¯] will be too low, and because Ksp(1/2) x [OH-]³ the calculated Ksp value will betoo low.Ksp = (1/2) x [OH¯]³ and since the [H30+] does not appear in that formula, the calculated Ksp value will be unaffected.Because the student is adding too much HCI, the calculated [H30+] will be too high. Since H30+ and OH- react in a 1:1 ratio, the implied [OH-] will be too high, and because Ksp(1/2) x [OH-]3 the calculated Kspvalue will be too high.

Given that HCl is added in excess during the titration. Since HCl is a source of H+(aq) that reacts…

A student adds too much HCI during the titration. Will the calculated Ksp be too high, too low, or unaffected? Why? O Because the student is adding too much HCI, the calculated [H30*] will be too high. Since Kw = [H30*]· [OH¯], the implied [OH¯] will be too low, and because Kso = (1/2) x [OH ]3 the calculated Ksp value will be too low. O Ksp = (1/2) x [OH ]3 and since the [H30*] does not appear in that formula, the calculated Ksp value will be unaffected. O Because the student is adding too much HCI, the calculated [H30+] will be too high. Since H30* and OH- react in a 1:1 ratio, the implied [OH-] will be too high, and because Ksp = (1/2) x [OH-]3 the calculated Ksp value will be too high.

A student adds too much HCI during the titration. Will the calculated Ksp be too high, too low, or unaffected? Why? O Because the student is adding too much HCI, the calculated [H30] will be too high. Since Kw = [H30]· [OH¯], the implied [OH¯] will be too low, and because Kso = (1/2) x [OH ]3 the calculated Ksp value will be too low. O Ksp = (1/2) x [OH ]3 and since the [H30] does not appear in that formula, the calculated Ksp value will be unaffected. O Because the student is adding too much HCI, the calculated [H30+] will be too high. Since H30 and OH- react in a 1:1 ratio, the implied [OH-] will be too high, and because Ksp = (1/2) x [OH-]3 the calculated Ksp value will be too high.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter15: Acid-base Equilibria

Section: Chapter Questions

Problem 118CWP: Consider the titration of 100.0 mL of 0.200 M HONH2 by 0.100 M HCI. (Kb for HONH2 = 1.1 108.) a....

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