9) An unknown weak acid is titrated to its equivalence point using 10 mL of 1M NaOH. At the equivalence point, the pH of the 100 mL solution is 9. What is the pKa of the acid? Knowing that, what was the pH of the original 90 mL solution? mol NaOH = (10ML) (IM) = 10 mmol [x-] = 10mmol 100mL = 0.1M pka: pH
9) An unknown weak acid is titrated to its equivalence point using 10 mL of 1M NaOH. At the equivalence point, the pH of the 100 mL solution is 9. What is the pKa of the acid? Knowing that, what was the pH of the original 90 mL solution? mol NaOH = (10ML) (IM) = 10 mmol [x-] = 10mmol 100mL = 0.1M pka: pH
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![9) An unknown weak acid is titrated to its equivalence point using 10 mL of 1M NaOH. At the equivalence point, the pH
of the 100 mL solution is 9. What is the pKa of the acid? Knowing that, what was the pH of the original 90 mL solution?
mol NaOH = (10ML) (IM) = 10 mmol
[x-] = 10mmol
100mL
= 0.1M
pka:
pH](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd7022bb2-a7ee-4272-8746-6f82499f4d6b%2F6b0b8a55-f4d9-4eec-a4f2-d83907e09145%2F83x2rll_processed.jpeg&w=3840&q=75)
Transcribed Image Text:9) An unknown weak acid is titrated to its equivalence point using 10 mL of 1M NaOH. At the equivalence point, the pH
of the 100 mL solution is 9. What is the pKa of the acid? Knowing that, what was the pH of the original 90 mL solution?
mol NaOH = (10ML) (IM) = 10 mmol
[x-] = 10mmol
100mL
= 0.1M
pka:
pH
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