Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with 0.100M HNO3 after 10.0 mL of the strong acid has been added. The value of Kb for H2NNH2 is 3.0 x 10-6. PREV 1 2 3 4 NEXT Based on your ICE table and definition of Kb, set up the expression for Kb in order to determine the unknown. Do r combine or simplify terms. Ko 3.0 x 10-6 %D 5 RESET [0] [0.200] [0.0200] [0.100] [0.140] [0.175] [x] [2x] [0.200 + x] [0.200 - x] [0.0200 + x] [0.0200 - x] [0.100 + x] [0.100 - x] [0.140 + x] [0.140 - x] [0.175 + x] [0.175 - x]

Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with 0.100M HNO3 after 10.0 mL of the strong acid has been added. The value of Kb for H2NNH2 is 3.0 x 10-6. PREV 1 2 3 4 NEXT Based on your ICE table and definition of Kb, set up the expression for Kb in order to determine the unknown. Do r combine or simplify terms. Ko 3.0 x 10-6 %D 5 RESET [0] [0.200] [0.0200] [0.100] [0.140] [0.175] [x] [2x] [0.200 + x] [0.200 - x] [0.0200 + x] [0.0200 - x] [0.100 + x] [0.100 - x] [0.140 + x] [0.140 - x] [0.175 + x] [0.175 - x]

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter16: Reactions Between Acids And Bases

Section: Chapter Questions

Problem 16.51QE

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with 0.100 M HNO3 after
10.0 mL of the strong acid has been added. The value of Kb for H2NNH2 is 3.0 x 10-6.
PREV
1
2
4
NEXT
Based on your ICE table and definition of Kb, set up the expression for Kb in order to determine the unknown. Do not
combine or simplify terms.
3.0 x 10-6
%3D
5 RESET
[0]
[0.200]
[0.0200]
[0.100]
[0.140]
[0.175]
[x]
[2x]
[0.200 + x]
[0.200 - x]
[0.0200 + x]
[0.0200 - x]
[0.100 + x]
[0.100 - x]
[0.140 + x]
[0.140 - x]
[0.175 + x]
[0.175 - x]
II

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